NONRESIDENT TRAINING COURSE SEPTEMBER 1998 Navy Electricity and Electronics Training Series Module 6 — Introduction to Electronic Emission, Tubes, and Power Supplies NAVEDTRA 14178 DISTRIBUTION STATEMENT A: Approved for public release; distribution is unlimited. DISTRIBUTION STATEMENT A: Approved for public release; distribution is unlimited. PREFACE By enrolling in this self-study course, you have demonstrated a desire to improve yourself and the Navy. Remember, however, this self-study course is only one part of the total Navy training program. Practical experience, schools, selected reading, and your desire to succeed are also necessary to successfully round out a fully meaningful training program. COURSE OVERVIEW: To introduce the student to the subject of Electronic Emissions, Tubes, and Power Supplies who needs such a background in accomplishing daily work and/or in preparing for further study. THE COURSE: This self-study course is organized into subject matter areas, each containing learning objectives to help you determine what you should learn along with text and illustrations to help you understand the information. The subject matter reflects day-to-day requirements and experiences of personnel in the rating or skill area. It also reflects guidance provided by Enlisted Community Managers (ECMs) and other senior personnel, technical references, instructions, etc., and either the occupational or naval standards, which are listed in the Manual of Navy Enlisted Manpower Personnel Classifications and Occupational Standards , NAVPERS 18068. THE QUESTIONS: The questions that appear in this course are designed to help you understand the material in the text. VALUE: In completing this course, you will improve your military and professional knowledge. Importantly, it can also help you study for the Navy-wide advancement in rate examination. If you are studying and discover a reference in the text to another publication for further information, look it up. 1998 Edition Prepared by ETC Allen E. Carney Published by NAVAL EDUCATION AND TRAINING PROFESSIONAL DEVELOPMENT AND TECHNOLOGY CENTER NAVSUP Logistics Tracking Number 0504-LP-026-8310 Sailor’s Creed “I am a United States Sailor. I will support and defend the Constitution of the United States of America and I will obey the orders of those appointed over me. I represent the fighting spirit of the Navy and those who have gone before me to defend freedom and democracy around the world. I proudly serve my country’s Navy combat team with honor, courage and commitment. I am committed to excellence and the fair treatment of all.” TABLE OF CONTENTS CHAPTER PAGE 1 . Introduction to Electron Tubes 1-1 2. Special-Purpose Tubes 2-1 3. Power Supplies 3-1 APPENDIX I. Glossary AI-1 INDEX INDEX- 1 NAVY ELECTRICITY AND ELECTRONICS TRAINING SERIES The Navy Electricity and Electronics Training Series (NEETS) was developed for use by personnel in many electrical- and electronic-related Navy ratings. Written by, and with the advice of, senior technicians in these ratings, this series provides beginners with fundamental electrical and electronic concepts through self-study. The presentation of this series is not oriented to any specific rating structure, but is divided into modules containing related information organized into traditional paths of instruction. The series is designed to give small amounts of information that can be easily digested before advancing further into the more complex material. For a student just becoming acquainted with electricity or electronics, it is highly recommended that the modules be studied in their suggested sequence. While there is a listing of NEETS by module title, the following brief descriptions give a quick overview of how the individual modules flow together. Module 1, Introduction to Matter , Energy, and Direct Current , introduces the course with a short history of electricity and electronics and proceeds into the characteristics of matter, energy, and direct current (dc). It also describes some of the general safety precautions and first-aid procedures that should be common knowledge for a person working in the field of electricity. Related safety hints are located throughout the rest of the series, as well. Module 2, Introduction to Alternating Current and Transformers, is an introduction to alternating current (ac) and transformers, including basic ac theory and fundamentals of electromagnetism, inductance, capacitance, impedance, and transformers. Module 3, Introduction to Circuit Protection, Control, and Measurement, encompasses circuit breakers, fuses, and current limiters used in circuit protection, as well as the theory and use of meters as electrical measuring devices. Module 4, Introduction to Electrical Conductors, Wiring Techniques, and Schematic Reading, presents conductor usage, insulation used as wire covering, splicing, termination of wiring, soldering, and reading electrical wiring diagrams. Module 5, Introduction to Generators and Motors, is an introduction to generators and motors, and covers the uses of ac and dc generators and motors in the conversion of electrical and mechanical energies. Module 6, Introduction to Electronic Emission, Tubes, and Power Supplies, ties the first five modules together in an introduction to vacuum tubes and vacuum-tube power supplies. Module 7, Introduction to Solid-State Devices and Power Supplies, is similar to module 6, but it is in reference to solid-state devices. Module 8, Introduction to Amplifiers, covers amplifiers. Module 9 , Introduction to Wave-Generation and Wave-Shaping Circuits, discusses wave generation and wave-shaping circuits. Module 10, Introduction to Wave Propagation, Transmission Lines, and Antennas, presents the characteristics of wave propagation, transmission lines, and antennas. IV Module 11, Microwave Principles, explains microwave oscillators, amplifiers, and waveguides. Module 12, Modulation Principles, discusses the principles of modulation. Module 13, Introduction to Number Systems and Logic Circuits, presents the fundamental concepts of number systems, Boolean algebra, and logic circuits, all of which pertain to digital computers. Module 14, Introduction to Microelectronics, covers microelectronics technology and miniature and microminiature circuit repair. Module 15, Principles of Synchros, Servos, and Gyros, provides the basic principles, operations, functions, and applications of synchro, servo, and gyro mechanisms. Module 16, Introduction to Test Equipment, is an introduction to some of the more commonly used test equipments and their applications. Module 17, Radio-Frequency Communications Principles, presents the fundamentals of a radio- frequency communications system. Module 18, Radar Principles, covers the fundamentals of a radar system. Module 19, The Technician's Handbook, is a handy reference of commonly used general information, such as electrical and electronic formulas, color coding, and naval supply system data. Module 20, Master Glossary, is the glossary of terms for the series. Module 21, Test Methods and Practices, describes basic test methods and practices. Module 22, Introduction to Digital Computers, is an introduction to digital computers. Module 23, Magnetic Recording, is an introduction to the use and maintenance of magnetic recorders and the concepts of recording on magnetic tape and disks. Module 24, Introduction to Fiber Optics, is an introduction to fiber optics. Embedded questions are inserted throughout each module, except for modules 19 and 20, which are reference books. If you have any difficulty in answering any of the questions, restudy the applicable section. Although an attempt has been made to use simple language, various technical words and phrases have necessarily been included. Specific terms are defined in Module 20, Master Glossary. Considerable emphasis has been placed on illustrations to provide a maximum amount of information. In some instances, a knowledge of basic algebra may be required. Assignments are provided for each module, with the exceptions of Module 19, The Technician's Handbook ; and Module 20, Master Glossary. Course descriptions and ordering information are in NAVEDTRA 12061, Catalog of Nonresident Training Courses. v Throughout the text of this course and while using technical manuals associated with the equipment you will be working on, you will find the below notations at the end of some paragraphs. The notations are used to emphasize that safety hazards exist and care must be taken or observed. WARNING AN OPERATING PROCEDURE, PRACTICE, OR CONDITION, ETC., WHICH MAY RESULT IN INJURY OR DEATH IF NOT CAREFULLY OBSERVED OR FOLLOWED. CAUTION AN OPERATING PROCEDURE, PRACTICE, OR CONDITION, ETC., WHICH MAY RESULT IN DAMAGE TO EQUIPMENT IF NOT CAREFULLY OBSERVED OR FOLLOWED. NOTE An operating procedure, practice, or condition, etc., which is essential to emphasize. vi INSTRUCTIONS FOR TAKING THE COURSE ASSIGNMENTS The text pages that you are to study are listed at the beginning of each assignment. Study these pages carefully before attempting to answer the questions. Pay close attention to tables and illustrations and read the learning objectives. The learning objectives state what you should be able to do after studying the material. Answering the questions correctly helps you accomplish the objectives. SELECTING YOUR ANSWERS Read each question carefully, then select the BEST answer. You may refer freely to the text. The answers must be the result of your own work and decisions. You are prohibited from referring to or copying the answers of others and from giving answers to anyone else taking the course. SUBMITTING YOUR ASSIGNMENTS To have your assignments graded, you must be enrolled in the course with the Nonresident Training Course Administration Branch at the Naval Education and Training Professional Development and Technology Center (NETPDTC). Following enrollment, there are two ways of having your assignments graded: (1) use the Internet to submit your assignments as you complete them, or (2) send all the assignments at one time by mail to NETPDTC. Grading on the Internet: Advantages to Internet grading are: • you may submit your answers as soon as you complete an assignment, and • you get your results faster; usually by the next working day (approximately 24 hours). In addition to receiving grade results for each assignment, you will receive course completion confirmation once you have completed all the assignments. To submit your assignment answers via the Internet, go to: http://courses.cnet.navy.mil Grading by Mail: When you submit answer sheets by mail, send all of your assignments at one time. Do NOT submit individual answer sheets for grading. Mail all of your assignments in an envelope, which you either provide yourself or obtain from your nearest Educational Services Officer (ESO). Submit answer sheets to: COMMANDING OFFICER NETPDTC N331 6490 SAUFLEY FIELD ROAD PENSACOLA FL 32559-5000 Answer Sheets: All courses include one “scannable” answer sheet for each assignment. These answer sheets are preprinted with your SSN, name, assignment number, and course number. Explanations for completing the answer sheets are on the answer sheet. Do not use answer sheet reproductions: Use only the original answer sheets that we provide — reproductions will not work with our scanning equipment and cannot be processed. Follow the instructions for marking your answers on the answer sheet. Be sure that blocks 1, 2, and 3 are filled in correctly. This information is necessary for your course to be properly processed and for you to receive credit for your work. COMPLETION TIME Courses must be completed within 12 months from the date of enrollment. This includes time required to resubmit failed assignments. Vll PASS/FAIL ASSIGNMENT PROCEDURES If your overall course score is 3.2 or higher, you will pass the course and will not be required to resubmit assignments. Once your assignments have been graded you will receive course completion confirmation. If you receive less than a 3.2 on any assignment and your overall course score is below 3.2, you will be given the opportunity to resubmit failed assignments. You may resubmit failed assignments only once. Internet students will receive notification when they have failed an assignment— they may then resubmit failed assignments on the web site. Internet students may view and print results for failed assignments from the web site. Students who submit by mail will receive a failing result letter and a new answer sheet for resubmission of each failed assignment. COMPLETION CONFIRMATION After successfully completing this course, you will receive a letter of completion. ERRATA Errata are used to correct minor errors or delete obsolete information in a course. Errata may also be used to provide instructions to the student. If a course has an errata, it will be included as the first page(s) after the front cover. Errata for all courses can be accessed and viewed/downloaded at: http://www.advancement.cnet.navy.mil STUDENT FEEDBACK QUESTIONS For subject matter questions: E-mail: n3 1 5 .products @ cnet.navy.mil Phone: Comm: (850) 452-1001, ext. 1728 DSN: 922-1001, ext. 1728 FAX: (850)452-1370 (Do not fax answer sheets.) Address: COMMANDING OFFICER NETPDTC N315 6490 SAUFLEY FIELD ROAD PENSACOLA FL 32509-5237 For enrollment, shipping, grading, or completion letter questions E-mail: fleetservices@cnet.navy.mil Phone: Toll Free: 877-264-8583 Comm: (850)452-1511/1181/1859 DSN: 922-1511/1181/1859 FAX: (850)452-1370 (Do not fax answer sheets.) Address: COMMANDING OFFICER NETPDTC N331 6490 SAUFLEY FIELD ROAD PENSACOLA FL 32559-5000 NAVAL RESERVE RETIREMENT CREDIT If you are a member of the Naval Reserve, you will receive retirement points if you are authorized to receive them under current directives governing retirement of Naval Reserve personnel. For Naval Reserve retirement, this course is evaluated at 5 points. (Refer to Administrative Procedures for Naval Reservists on Inactive Duty , BUPERSINST 1001.39, for more information about retirement points.) We value your suggestions, questions, and criticisms on our courses. If you would like to communicate with us regarding this course, we encourage you, if possible, to use e-mail. If you write or fax, please use a copy of the Student Comment form that follows this page. vm Student Comments MEETS Module 6 Course Title: Introduction to Electronic Emissions, Tubes, and Power Supplies NAVEDTRA: 14178 Date: We need some information about you : Rate/Rank and Name: SSN: Command/Unit Street Address: City: State/FPO: Zip Your comments, suggestions, etc .: Privacy Act Statement: Under authority of Title 5, USC 301, information regarding your military status is requested in processing your comments and in preparing a reply. This information will not be divulged without written authorization to anyone other than those within POD for official use in determining performance. NETPDTC 1550/41 (Rev 4-00) IX CHAPTER 1 INTRODUCTION TO ELECTRON TUBES LEARNING OBJECTIVES Learning objectives are stated at the beginning of each chapter. These learning objectives serve as a preview of the information you are expected to learn in the chapter. The comprehensive check questions are based on the objectives. By successfully completing the OCC/ECC, you indicate that you have met the objectives and have learned the information. The learning objectives are listed below. Upon completion of this chapter, you will be able to: 1. State the principle of thermionic emission and the Edison Effect and give the reasons for electron movement in vacuum tubes. 2. Identify the schematic representation for the various electron tubes and their elements. 3. Explain how the diode, triode, tetrode, and pentode electron tubes are constructed, the purpose of the various elements of the tube, and the theory of operation associated with each tube. 4. State the advantages, disadvantages, and limitations of the various types of electron tubes. 5. Describe amplification in the electron tube, the classes of amplification, and how amplification is obtained. 6. Explain biasing and the effect of bias in the electron tube circuit. 7. Describe the effects the physical structure of a tube has on electron tube operation and name the four most important tube constants that affect efficient tube operation. 8. Describe, through the use of a characteristic curve, the operating parameters of the electron tube. INTRODUCTION TO ELECTRON TUBES In previous study you have learned that current flows in the conductor of a completed circuit when a voltage is present. You learned that current and voltage always obey certain laws. In electronics, the laws still apply. You will use them continuously in working with electronic circuits. One basic difference in electronic circuits that will at first seem to violate the basic laws is that electrons flow across a gap, a break in the circuit in which there appears to be no conductor. A large part of the field of electronics and the entire field of electron tubes are concerned with the flow and control of these electrons "across the gap." The following paragraphs will explain this interesting phenomenon. THERMIONIC EMISSION You will remember that metallic conductors contain many free electrons, which at any given instant are not bound to atoms. These free electrons are in continuous motion. The higher the temperature of the conductor, the more agitated are the free electrons, and the faster they move. A temperature can be 1-1 reached where some of the free electrons become so agitated that they actually escape from the conductor. They "boil" from the conductor’s surface. The process is similar to steam leaving the surface of boiling water. Heating a conductor to a temperature sufficiently high causing the conductor to give off electrons is called THERMIONIC EMISSION. The idea of electrons leaving the surface is shown in figure 1-1. UNHEATED Figure 1-1. — Thermionic emission. Thomas Edison discovered the principle of thermionic emission as he looked for ways to keep soot from clouding his incandescent light bulb. Edison placed a metal plate inside his bulb along with the normal filament. He left a gap, a space, between the filament and the plate. He then placed a battery in series between the plate and the filament, with the positive side toward the plate and the negative side toward the filament. This circuit is shown in figure 1-2. 1-2 AMMETER METAL PLATE GAP- FILAMENT Figure 1-2. — Edison's experimental circuit. When Edison connected the filament battery and allowed the filament to heat until it glowed, he discovered that the ammeter in the filament-plate circuit had deflected and remained deflected. He reasoned that an electrical current must be flowing in the circuit — EVEN ACROSS THE GAP between the filament and plate. Edison could not explain exactly what was happening. At that time, he probably knew less about what makes up an electric circuit than you do now. Because it did not eliminate the soot problem, he did little with this discovery. However, he did patent the incandescent light bulb and made it available to the scientific community. Let's analyze the circuit in figure 1-2. You probably already have a good idea of how the circuit works. The heated filament causes electrons to boil from its surface. The battery in the filament-plate circuit places a POSITIVE charge on the plate (because the plate is connected to the positive side of the battery). The electrons (negative charge) that boil from the filament are attracted to the positively charged plate. They continue through the ammeter, the battery, and back to the filament. You can see that electron flow across the space between filament and plate is actually an application of a basic law you already know— UNLIKE CHARGES ATTRACT. Remember, Edison's bulb had a vacuum so the filament would glow without burning. Also, the space between the filament and plate was relatively small. The electrons emitted from the filament did not have far to go to reach the plate. Thus, the positive charge on the plate was able to attract the negative electrons. The key to this explanation is that the electrons were floating free of the hot filament. It would have taken hundreds of volts, probably, to move electrons across the space if they had to be forcibly pulled from a cold filament. Such an action would destroy the filament and the flow would cease. The application of thermionic emission that Edison made in causing electrons to flow across the space between the filament and the plate has become known as the EDISON EFFECT. It is fairly simple 1-3 and extremely important. Practically everything that follows will be related in some way to the Edison effect. Be sure you have a good understanding of it before you go on. Ql. How can a sheet of copper be made to emit electrons thermionically? Q2. Why do electrons cross the gap in a vacuum tube ? THE DIODE TUBE The diode vacuum tube we are about to study is really Edison’s old incandescent bulb with the plate in it. Diode means two elements or two electrodes, and refers to the two parts within the glass container that make up the tube. We have called them filament and plate. More formally, they are called CATHODE and PLATE, respectively. Sometimes the filament is called a HEATER, for obvious reasons-more on this later. Within a few years after the discovery of the Edison effect, scientists had learned a great deal more than Edison knew at the time of his discovery. By the early 1900s, JJ. Thomson in England had discovered the electron. Marconi, in Italy and England, had demonstrated the wireless, which was to become the radio. The theoretical knowledge of the nature of electricity and things electrical was increasing at a rapid rate. J.A. Fleming, an English scientist, was trying to improve on Marconi’s relatively crude wireless receiver when his mind went back to Edison’s earlier work. His subsequent experiments resulted in what became known as the FLEMING VALVE (the diode), the first major step on the way to electronics. OPERATION OF THE DIODE TUBE Before learning about Fleming’s valve, the forerunner of the modern diode, let’s look at Edison’s original circuit. This time, however, well draw it as a schematic diagram, using the symbol for a diode instead of a cartoon-like picture. The schematic is shown in figure 1-3. PLATE FILAMENT SI PLATE SUPPLY FILAMENT SUPPLY Figure 1-3. — Schematic of Edison's experimental circuit. Note that this is really two series circuits. The filament battery and the filament itself form a series circuit. This circuit is known as the filament circuit. 1-4 The path of the second series circuit is from one side of the filament, across the space to the plate, through the ammeter and battery, then back to the filament. This circuit is known as the plate circuit. You will note that a part of the filament circuit is also common to the plate circuit. This part enables the electrons boiled from the filament to return to the filament. No electron could flow anywhere if this return path were not completed. The electron flow measured by the ammeter is known as plate current. The voltage applied between the filament and plate is known as plate voltage. You will become familiar with these terms and with others that are commonly used with diodes and diode circuits as we progress. Diode Operation with a Positive Plate Fleming started with a two-element tube (diode) similar to Edison’s and at first duplicated Edison’s experiment. The results are worth repeating here. Look at figure 1-3 again. With the plate POSITIVE relative to the filament, the filament hot, and the circuit completed as shown, the ammeter detected a current flowing in the plate circuit. Because current is the same in all parts of a series circuit, we know that the same current must flow across the space between filament and plate. We know now that the electrons boiled from the heated filament are NEGATIVE and are attracted to the POSITIVE plate because UNLIKE CHARGES ATTRACT. Diode Operation with a Negative Plate Fleming’s next step was to use a similar circuit but to reverse the plate battery. The circuit is shown in figure 1-4. AMMETER f SUPPLY Figure 1-4. — Diode with a negative plate. With the plate NEGATIVE relative to the filament, the filament hot, and the circuit completed as shown, the ammeter indicated that ZERO current was flowing in the plate circuit. Fleming found that the NEGATIVE charge on the plate, relative to the filament, CUT OFF the flow of plate current as effectively as if a VALVE were used to stop the flow of water in a pipe. 1-5 You have all of the facts available that Fleming had. Can you give an explanation of why the diode cuts off current when the plate is negative? Let’s put the facts together. The filament is hot and electrons boil from its surface. Because the filament is the only heated element in the diode, it is the ONLY source of electrons within the space between filament and plate. However, because the plate is NEGATIVE and the electrons are NEGATIVE, the electrons are repelled back to the filament. Remember that LIKE CHARGES REPEL. If electrons cannot flow across the space, then no electrons can flow anywhere in the plate circuit. The ammeter therefore indicates ZERO. It might seem to you that electrons flow from the negative plate to the positive filament under these conditions. This is NOT the case. Remember that it takes a heated element to emit electrons and that the filament is the only heated element in the diode. The plate is cold. Therefore, electrons cannot leave the plate, and plate -to-filament current cannot exist. The following is a summary of diode operation as we have covered it to this point: Assume that all parts of the circuit are operable and connected. • PLATE CURRENT FLOWS WHEN THE PLATE IS POSITIVE. • PLATE CURRENT IS CUT OFF WHEN THE PLATE IS NEGATIVE. • PLATE CURRENT FLOWS ONLY IN ONE DIRECTION -FROM THE FILAMENT TO THE PLATE. Measuring Diode Voltages As you know, it is impossible to have a voltage at one point, because voltage is defined as a DIFFERENCE of POTENTIAL between two points. In our explanation above we referred to plate voltage. To be exactly right, we should refer to plate voltage as the VOLTAGE BETWEEN PLATE and FILAMENT. Plate voltages, and others that you will learn about soon, are often referred to as if they appear at one point. This should not confuse you if you remember your definition of voltage and realize that voltage is always measured between two points. Ml and M2 in figure 1-5 measure plate voltage and filament voltage, respectively. Epri Ip ov 1-6 The reference point in diode and other tube circuits is usually a common point between the individual circuits within the tube. The reference point (common) in figure 1-5 is the conductor between the bottom of the transformer secondary and the negative side of the filament battery. Note that one side of each voltmeter is connected to this point. Name the two series circuits that exist in a diode circuit. Before a diode will conduct , the cathode must be what polarity relative to the plate ? Diode Operation with an Alternating Voltage on the Plate After experimenting with a positive plate and a negative plate, Fleming replaced the direct voltage of the battery with an alternating voltage. In our explanation, well use a transformer as the source of alternating voltage. The circuit is shown in figure 1-5. Note that the only real difference in this circuit from the previous ones is the transformer. The transformer secondary is connected in series with the plate circuit — where the plate battery was previously. Remember from your study of transformers that the secondary (output) of a transformer always produces an alternating voltage. The secondary voltage is a sine wave as shown in the figure. You'll remember that the sine wave is a visual picture, a graph of the change in alternating voltage as it builds from zero to a maximum value (positive) and then drops to zero again as it decreases to its minimum value (negative) in the cycle. Assume that the polarity across the secondary during the first half-cycle of the input ac voltage is as shown in the figure. During this entire first half-cycle period, the plate's polarity will be POSITIVE. Under this condition, plate current flows, as shown by the ammeter. The plate current will rise and fall because the voltage on the plate is rising and falling. Remember that current in a given circuit is directly proportional to voltage. During the second half-cycle period, plate's polarity will be NEGATIVE. Under this condition, for this entire period, the diode will not conduct. If our ammeter could respond rapidly, it would drop to zero. The plate-current waveform (I p ) in figure 1-5 shows zero current during this period. Here is a summary of effects of applying alternating voltage to the plate of the diode: 1 . Diode plate current flows during the positive half-cycle. It changes value as the plate voltage rises and falls. 2. The diode cuts off plate current during the entire period of the negative half-cycle. 3. Diode plate current flows in PULSES because the diode cuts off half the time. 4. Diode plate current can flow in only one direction. It is always a direct current. (In this case PULSATING DC — one that flows in pulses.) 5. In effect, the diode has caused an alternating voltage to produce a direct current. The ability to obtain direct current from an ac source is very important and one function of a diode that you will see again and again wherever you work in electronics. Q3. Q4. 1-7 The circuits that we have discussed up to this point were chosen to show the general concepts discovered by Edison and Fleming. They are not practical because they do no useful work. For now, only the concepts are important. Practical circuitry will be presented later in this chapter as you learn specific points about the construction, limitations, and other characteristics of modern diode tubes. Q5. An ac voltage is applied across a diode. The tube will conduct when what alternation of ac is applied to the plate ? Q6. What would be the output of the circuit described in question 5? DIODE CONSTRUCTION Diode tubes in present use are descendants of Fleming’s valve. There is a family resemblance, but many changes have been made from the original. Diodes are both smaller and larger, less powerful and more powerful, and above all, more efficient and more reliable. The search for greater efficiency and reliability has resulted in many physical changes, a few of which will be covered in the next paragraphs. Most of what is said here about construction and materials will be true of all electron tubes, not just diodes. Filaments Modern filaments in ALL tubes last longer, emit greater amounts of electrons for a given size, and many operate at a lower temperature than in the early days. Most improvements have resulted from the use of new materials and from better quality control during manufacture. Three materials that are commonly used as filaments are tungsten, thoriated tungsten, and oxide-coated metals. Tungsten has great durability but requires large amounts of power for efficient thermionic emission. Thoriated-tungsten filaments are made of tungsten with a very thin coat of thorium, which makes a much better emitter of electrons than just tungsten. Oxide-coated filaments are made of metal, such as nickel, coated with a mixture of barium and strontium oxides. The oxide coat, in turn, is coated with a one- molecule-thick layer of metal barium and strontium. Oxide coating produces great emission efficiency and long life at relatively low heat. A major advance in electronics was the elimination of batteries as power sources for tubes. Except in electronic devices designed to be operated away from the ac power source, alternating current is used to heat filaments. Voltage may be supplied by a separate filament transformer or it may be taken from a filament winding that is part of a power transformer. The actual voltage may vary from 1 volt up and depends on the design of the tube. Common filament voltages are 5.0, 6.3, and 12.6 volts ac. Filaments may be connected in series with other tube filaments or may be in parallel with each other. This is determined by the equipment designer. Cathodes As was mentioned previously, a more formal name for the electron-emitting element in a tube is the CATHODE. Cathodes in all tubes, not just diodes, are of two general types, either directly heated or indirectly heated. Each has its advantages and disadvantages. 1-8 DIRECTLY HEATED. — The filament that has been discussed so far is the directly heated cathode. Directly heated cathodes are fairly efficient and are capable of emitting large amounts of electrons. Figure 1-6 shows this type and its schematic symbol. SUPPORT -FILAMENT DIRECTLY HEATED SCHEMATIC CONSTRUCTION Figure 1-6. — Cathode schematic representation. An added advantage of this type of filament is the rapidity with which it reaches electron-emitting temperature. Because this is almost instantaneous, many pieces of electronic equipment that must be turned on at infrequent intervals and be instantly usable have directly heated cathode tubes. There are disadvantages. Because of its construction, parts of the filament are closer to the plate than other parts. This results in unequal emission and a loss of efficiency. Another disadvantage occurs when dc is used to heat a filament. The filament represents a resistance. When current flows through this resistance, a voltage drop occurs. The result is that one side of the resistance, or filament, is more negative than the other side. The negative side of the filament will emit more electrons than the positive side; which, again, is less efficient than if the filament has equal emission across its entire surface. When ac is the source of filament power, it causes a small increase and decrease of temperature as it rises and falls. This causes a small increase and decrease of emitted electrons. This effect is not too important in many diode circuits, but it is undesirable in other tube circuits. INDIRECTLY HEATED. — Figure 1-7 shows this type of cathode and its schematic symbol. Indirectly heated cathodes are always composed of oxide-coated material. The cathode is a cylinder, a kind of sleeve, that encloses the twisted wire filament. The only function of the filament is to heat the cathode. The filament is often called a heater when used in this manner. CATHODE HEATER ► SCHEMATIC OXIDE-COATED CATHODE SLEEVE HEATER FILAMENT CONSTRUCTION Figure 1-7. — Indirectly heated cathode schematic. 1-9 Some schematics do not show heaters and heater connections. Heaters, of course, are still present in the tubes, but their appearance in a schematic adds little to understanding the circuit. The heater is not considered to be an active element. For example, a tube with an indirectly heated cathode and a plate is still called a diode, even though it might seem that there are three elements in the tube. Because indirectly heated cathodes are relatively large, they take longer to heat to electron-emitting temperature. Once up to temperature, however, they do not respond to the small variations in heater temperature caused by ac fluctuations. Because of the inherent advantages, most tubes in use today have indirectly heated cathodes. Q7. Besides tungsten, what other materials are used for cathodes in vacuum tubes? Q8. What is the advantage of directly heated cathodes? Plates Edison’s plate was just that-a plate, a flat piece of metal. Plates are no longer flat but are designed in many different shapes. Figure 1-8 shows two diodes, one with a directly heated cathode, the other with an indirectly heated cathode. Each plate is cut away to show the internal position of elements and the plate shapes. PLATE Figure 1-8. — Cutaway view of plate construction. Plates must be able to hold up under the stress of heat created by the flow of plate currents and the closeness of hot cathodes. They need to be strong enough to withstand mechanical shocks produced by vibration and handling. Some typical materials used for electron tube plates are tungsten, molybdenum, graphite, nickel, tantalum, and copper. Tube Bases The base shown in figure 1-9 has two functions. First, it serves as the mounting for tube elements. Second, it serves as the terminal points for the electrical connections to the tube elements. This is accomplished by molding or otherwise bringing pins (or prongs) through the base. The internal ends of these pins are connected to tube elements. The pins themselves are male connections. 1-10 GLASS ENVELOPE Figure 1-9. — Diode construction. The base must be mechanically strong and made of an insulating material to prevent the tube elements from shorting. Because they require relatively frequent replacement, most tubes are designed to plug into sockets permanently mounted in the equipment. Tube pins and sockets are so designed that tubes cannot be plugged in incorrectly. Tube sockets must make secure mechanical and electrical contact with tube pins, must insulate pins from each other, and must provide terminals to which circuit components and conductors are connected. Each element of a tube is connected to a pin in its base. To trace a circuit easily and efficiently, you must match elements with their pin numbers. This information is available in tube manuals and equipment schematics. Figure 1-10 shows these numbers on one example of a diode symbol. You will also note the designation V 1 beside the tube. Electron tubes are often identified in schematic diagrams by the letter V and a number. 1-11 Figure 1-10. — Identification of tube elements. Now, to use the information in the symbol, you need to know the system used to number tube pins and socket connections. Figure 1-11 shows five common pin configurations as viewed from the bottom of each tube or socket. This is important. In every case, pins and pin connections on sockets are numbered in a clockwise direction— WHEN VIEWED FROM THE BOTTOM. 7 PIN MINIATURE 9 PIN MINIATURE Figure 1-11. — Pin Identification; all tubes are viewed from the bottom. In each of the five pictures in figure 1-11, there is an easily identified point from which to start numbering. In the 4-prong and 6-prong tubes, the point is between the two larger prongs. In the octal tube, the point is directly down from the key way in the center of the tube. In the 7-pin and 9-pin miniatures, the point is identified by the larger distance between pins. Q9. Name two functions of the base of a vacuum tube. The Envelope The envelope of a tube may be made of ceramic, metal, or glass. Its major purpose is to keep the vacuum in and the atmosphere out. The main reason for this is that the heated filament would burn up in the atmosphere. There are other reasons for providing a vacuum, but the important thing is to realize that a tube with a leaky envelope will not function properly. 1-12 The silver spot you will sometimes see on the inside surface of the glass envelope of a vacuum tube is normal. It was caused by the "flashing" of a chemical during the manufacture of the tube. Burning the chemical, called the GETTER, helps to produce a better vacuum and eliminates any remaining gases. ELECTRICAL PARAMETERS OF DIODES Thousands of different tubes exist. While many of them are similar and even interchangeable, many have unique characteristics. The differences in materials, dimensions, and other physical characteristics, such as we have just covered, result in differing electrical characteristics. The electrical parameters of a diode, and any tube, are specific. In the process of discussing these parameters, we will state exact values. Voltages will be increased and decreased and the effects measured. Limiting factors and quantities will be explored and defined. The discussion will be based on simplified and experimental circuits. It is important for you to realize that practically all of the parameters, limitations, definitions, abbreviations, and so on that we will cover in these next paragraphs will apply directly to the more complex tubes and circuits you will study later. Diode parameters are the foundation for all that follows. Symbols You have learned to use letters and letter combinations to abbreviate or symbolize electrical quantities. (The letters E, I, and R are examples.) We will continue this practice in referring to tube quantities. You should be aware that other publications may use different abbreviations. Many attempts have been made to standardize such abbreviations, inside the Navy and out. None have succeeded completely. Table 1-1 lists electron-tube symbols used in the remainder of this chapter. The right-hand column shows equivalent symbols that you may find in OTHER texts and courses. Table 1-1. — Symbols for Tube Parameters SYMBOLS THIS TEXT MEANING OTHER TEXTS E P PLATE VOLTAGE, D.C. VALUE Ebb PLATE SUPPLY VOLTAGE, D.C. B+ E c GRID BIAS VOLTAGE, D.C. VALUE E, E cc GRID BIAS SUPPLY VOLTAGE, D.C. C- e b INSTANTANEOUS PLATE VOLTAGE Cc INSTANTANEOUS GRID VOLTAGE e 2 A.C. COMPONENT OF GRID VOLTAGE e P A.C. COMPONENT OF PLATE VOLTAGE (ANODE) Ip D.C. PLATE CURRENT R P D.C. PLATE RESISTANCE R* GRID RESISTANCE R k CATHODE RESISTANCE Rl LOAD RESISTANCE Plate Voltage-Plate Current Characteristic You know that a positive voltage on the diode plate allows current to flow in the plate circuit. Each diode, depending on the physical and electrical characteristics designed into the diode, is able to pass an exact amount of current for each specific plate voltage (more voltage, more current-at least to a point). 1-13 The plate voltage-plate current characteristic for a given diode is a measure of exactly how much plate voltage controls how much plate current. This is often called the E p - I p characteristic. The E p - I p characteristic for a given diode, is determined by design engineers using mathematical analysis and laboratory experiment. You, as a technician, will never need to do this. However, you will use the results obtained by the engineers. You will also use your knowledge of the diode as you analyze equipment malfunction. Assume that we have the circuit in figure 1-12. (The filament has the proper voltage-even though it isn’t shown on the diagram.) Our purpose is to determine just how a changing voltage on the plate changes (or controls) the plate current. The method is as follows: VARIABLE D.C. PLATE VOLTAGE SUPPLY Figure 1-12. — Determining diode plate characteristic. 1. Starting with zero volts from our variable dc voltage source, increase the plate voltage (E p ) in steps of 50 volts until you reach 400 volts. 2. At a each 50-volt step, measure the milliamperes of plate current (I p ) that flow through the meter. Record the I p meter readings, step by step, so that you may analyze the results. Assume that table 1-2 shows our results. While we could use the table, a more normal procedure is to plot a graph of the values. Such a graph is called an E p - I p CURVE and is shown in figure 1-13. Each tube has its own E p - I p curve, which is available in commercial tube manuals and in many equipment technical manuals. Each curve will be different in some respects from every other curve. The shapes, however, will be similar. Table 1-2. — E p - I p Values Obtained by Experiment E P 0 50 100 150 200 250 300 350 400 Ip 0 .002 .005 .010 .020 .030 .040 .042 .045 1-14 PLATE VOLTAGE (Ep) (VOLTS) Figure 1-13. — E p - I p characteristic curve. The E p - I p curve in figure 1-13, although just an example, is typical of real plate characteristic curves. You may learn certain characteristics that apply to both diodes and other tubes by studying it. First, look at the part of the curve to the left of point A. Because it is not a straight line, it is referred to as NONLINEAR. Note that a change of 150 volts (0-150) caused a change of 10 mA of plate current (0-10). In comparison with the straight-line part of the curve, between points A and B, this is a relatively small change in current. The smaller the change in current, the flatter the curve. In explaining this NONLINEAR portion of the curve, let’s go back just a bit to electron emission. The electrons emitted by a cathode form a cloud around the cathode. This cloud is called the SPACE CHARGE. The closer the space charge is to the cathode, the more densely packed it is with electrons. In our example, the lower plate voltages (0-150 volts) over this part of the curve exert a pull on only the outer fringe of the space charge where there are few electrons. This results in relatively few electrons flowing to the plate. Now look at the center portion of the curve between A and B. This is known as the LINEAR portion because it is nearly a STRAIGHT LINE. Over this portion, a change of 50 volts E p causes a change of 10 mA I p . The reason for the increased change in plate current for a given change of plate voltage also has to do with the space charge. With a higher plate voltage (over 150 volts), the attraction from the plate begins to influence the DENSER part of the space charge that has greater numbers of electrons. Therefore, a higher current flows for a given voltage than in the nonlinear part. The curve becomes steeper. In our example, this linearity continues to about 300 volts, point B. Lastly, let’s look at the top portion of the curve. The plate current plotted here is produced by the higher plate voltages. However, the amount of current change for a given voltage change is greatly reduced. The reason for this again involves the space charge. At about 300 volts, almost all of the electrons in the space charge are flowing to the plate. A higher voltage cannot attract more electrons because the cathode cannot produce any more. The point where all (or almost all) available electrons are being drawn to the plate is called PLATE SATURATION or just SATURATION. This is one of the limiting factors of every tube. 1-15 You can see from the analysis that the most consistent control of plate current takes place over the linear portion of the E p - I p curve. In most applications, electron tubes are operated in this linear portion of the characteristic curve. Plate Resistance (R p ) One tube parameter that can be calculated from values on the E p - I p curve is known as plate resistance, abbreviated as R p . In a properly designed electron tube, there is no physical resistor between cathode and plate; that is, the electrons do not pass through a resistor in arriving at the plate. You may have wondered, however, why the variable dc voltage source of figure 1-12 didn’t blow a fuse. Doesn’t the plate circuit appear to be a short circuit-a circuit without a load to limit the current? The fact is, there is a very real, effective RESISTANCE between cathode and plate. It is not lumped in a resistor, but the circuit may be analyzed as if it is. The plate resistance of a given tube, R p , can be calculated by applying Ohm’s law to the values of E p and I p . Figure 1-14 is a typical diode E p - I p curve. The plate resistance has been figured for R p under three different conditions, as follows: Figure 1-14. — The E p - 1 characteristic curve for a diode. Remember that 1 mA = .001 ampere; therefore 40 mA =.040 ampere. Solution: 20volts k p — .040 amperes Rp = 500 ohms The other two indicated values of R p were figured in the same way. 1-16 You should note that there is very little difference in plate resistance when the E p and I p values are taken from the linear portions of curves. Check this out with values taken from the linear portion of figure 1 - 13 . R p (with a capital R) is the effective resistance offered to direct current. PLATE RESISTANCE IN GAS DIODES. — Gas diodes are a type of tube that we have not yet discussed. They are mentioned here only because of their plate-resistance characteristic. Instead of a high- vacuum environment, some tubes have small amounts of gas introduced in the envelope vacuum during manufacture. Argon, neon, helium, or mercury vapor are commonly used. When a certain minimum voltage is placed on the plate, the gas molecules in the envelope ionize. This happens by a process that will be explained when gas diodes are studied. The positive ions tend to cancel some of the effects of the space charge that influence plate resistance in a vacuum tube. This canceling reduces internal plate resistance to a relatively low, constant value. In applications that require a large plate current, the low plate resistance of a gas-filled diode has an efficiency that cannot be approached by a high- vacuum diode. This and other characteristics of gas tubes will be covered later. Q10. Vacuum tubes are designed to operate in what portion of the E p - I p curve? Qll. What value can be calculated from the values found on an E p - I p curve? Plate Dissipation When electrons are attracted from the space charge to the plate, they are accelerated by the attraction. Their gain in speed gives them energy that causes them to strike the plate with a considerable force. As the electrons strike the plate, this energy is converted to heat. The plate must be able to withstand the associated increase in temperature. The maximum amount of power (watts) that a given plate can safely dissipate (as heat) is called the PLATE DISSIPATION rating. To find the amount of plate dissipation for a given tube under a particular set of plate conditions, use the following equation: Plate dissipation = Epx Ip For our current problem, Plate dissipation = 20 volts x .040 amperes Plate dissipation = .8 watt This is a relatively small wattage. It's probable that the plate of our example diode is not overheating. A tube manual could tell us for sure. Plate dissipation is a circuit loss that must be made good by the power source in a circuit. In our example, this is the plate voltage supply. 1-17 Peak Current Rating The maximum instantaneous current that a tube can pass in the normal direction (cathode to plate) without damage is called the PEAK CURRENT RATING. Peak current rating is determined by the amount of electrons available from the cathode and the length of time plate current flows. Peak Voltage Rating This is the maximum instantaneous voltage that can be applied to a tube in the normal direction without a breakdown. Peak Inverse Voltage Rating This is the maximum voltage that can be applied to a tube in the reverse direction (plate negative with respect to the cathode)-exceeding this will cause arc -over from the plate to the cathode and will damage the tube. PIV, as this is sometimes abbreviated, becomes very important in the rectifier circuit to be discussed as a later major subject. Transit Time Things that happen in electricity and electronics are often explained as if they happen instantaneously. As fast as electricity acts, however, the truth is that cause and effect are separated by a certain amount of time. Each tube has a factor called TRANSIT TIME, which is the time required for an individual electron to move from the cathode to the plate. In certain applications involving high-frequency voltages, transit time places a limitation on tubes. We will explain this limitation when we discuss the circuits it affects. Summary of Diode Parameters and Limitations You should now have a basic understanding of diodes, many of their characteristics, and some of their limitations. One of the more important concepts that you should now understand is that most of these characteristics influence each other. For example, practically all plate characteristics are interrelated. Change one and the others change. Another example is heater voltage. Every tube parameter affected by the cathode depends on proper heater voltage. Interrelationships such as these make electronics both fascinating and, at times, frustrating. Many of the limiting factors that we have discussed are the same ones found in other electrical devices such as motors, stoves, toasters, and so on. Heating and overheating, insulation breakdown, and excessive voltage and current are all limitations that you have noted before. The point is that you can and should apply just about everything you have learned about electricity to electron tubes. Little is new except the environment. Q12. A large negative voltage is applied to the plate of a diode, and a large positive voltage is applied to the cathode. If the tube conducts, what tube parameter has been exceeded? THE TRIODE Diode electron tubes can be used as rectifiers, switches, and in many other useful applications. They are still used in Fleming’s original application in some radio circuits. You will learn more of these 1-18 applications in other NEETS modules and later will see the diode in several pieces of electronic equipment. As with all inventions, Fleming’s diode was immediately the subject of much experimentation and many attempts at improvement. An American experimenter, Dr. Lee De Forest, added another active element to the diode in 1906. He was trying to improve the radio application of Fleming’s diode. His new tube was eventually called a triode. DeForest’s triode was not very successful as a radio "detector." (Detectors will be studied in a later NEETS module.) However, in 1912, De Forest discovered that his original triode could AMPLIFY or magnify very weak electrical impulses. It is because of the triode’s ability to amplify that De Forest is honored as one of the great radio pioneers. The immediate application of the triode amplifier was in telephone and radio. Both fields were limited because electrical impulses (signals) became weaker and weaker as the distance from the signal source increased. The triode, along with other developments of the time, made long-distance communications possible. Looking back, we can now see that the amplifying tube was the real beginning of modern electronics and influenced everything that followed. Let’s find out more about the idea of amplification and how it is done in the triode. You are already familiar with a type of amplification. In a previous NEETS module, step-up transformers were discussed. You should remember that an input voltage applied to the primary of a step- up transformer is increased in amplitude at the secondary by a factor determined by the step-up turns ratio. For example, if 5 volts were applied to the primary of a 1:3 step-up transformer, the secondary would produce 15 volts. In other words, the input voltage was amplified by a factor of 3. When applied to electronic circuits, these primary and secondary voltages are more often called signals, or input and output signal, respectively. In electronics, the amplitude of an input signal must sometimes be increased many times-often, hundreds or thousands of times! Because of size and design limitations, transformers are usually not practical for use in electronics as amplifiers. DeForest’s first experiment with the diode was to place an additional metal plate between the cathode and plate. He then placed an ac signal on the metal plate. When the circuit was energized, De Forest found that the ammeter stayed on zero regardless of the polarity of the input signal. What was happening was that the new element was blocking (or shadowing) the plate. Any electrons attempting to reach the plate from the cathode would hit the new element instead. As the circuit didn’t work, it was back to the drawing board. In his next attempt, De Forest decided to change the element between the cathode and the plate. Instead of a solid metal plate, he used a wire mesh. This would allow electrons to flow from the cathode, THROUGH THE WIRE MESH, to the plate. This tube circuit is shown in figure 1-15. In view (A) you see De Forest’s circuit with 0 volts applied to the third element, (today called a control grid or occasionally just the grid). Under these conditions, assume that the ammeter reads 5 milliamperes. With no voltage applied to the grid, the grid has little effect on the electron stream. For all practical purposes, the control grid is not there. Most electrons flow through the open mesh. The tube functions as a diode. 1-19 5 MILLIAMPERES 10 MLLIAMPERES 25 MLLIAMPERES Figure 1-15. — DeForest’s experiment. In view (B), you see De Forest’s tube with +3 volts applied to the control grid. When De Forest applied this voltage, he found that plate current, I p , increased by a large amount. (Well say it doubled to simplify the explanation.) You already know that the only way to double the plate current in a diode is to increase the plate voltage by a large amount. Yet, De Forest had doubled plate current by applying only 3 volts positive to the control grid! The reason for this is fairly easy to understand. It’s the old principle of "opposites attract." When the control grid was made positive, electrons surrounding the cathode (negative charges) were attracted to the grid. But remember, the grid is a metal mesh. Most of the electrons, instead of striking the grid wires, were propelled through the holes in the mesh. Once they had passed the grid, they were attracted to the positive charge in the plate. You might wonder why the grid would make that much difference. After all, the plate has 300 volts on it, while the grid only has 3 volts on it. Surely the plate would have a greater effect on current flow than a grid with only one one-hundredth the attractive potential of the plate. But remember, in your study of capacitors you discovered that opposites attract because of electrostatic lines of force, and that the strength of electrostatic lines of force decreased with distance. In his tube, DeForest had placed the grid very close to the cathode. Therefore, it had a greater effect on current flow from the cathode than did the plate, which was placed at a much greater distance from the cathode. For this reason, De Forest was able to double the current flow through the tube with only +3 volts applied to the grid. DeForest had certainly hit on something. Now the problem was to find out what would happen when a negative potential was applied to the grid. This is shown in view (C) of figure 1-15. When De Forest applied -3 volts to the grid, he found that plate current decreased to half of what it was when the grid had no voltage applied. The reason for this is found in the principle of "likes repel." The negatively charged grid simply repelled some of the electrons back toward the cathode. In this manner, the attractive effect of the plate was decreased, and less current flowed to the plate. Now De Forest was getting somewhere. Using his new tube (which he called a triode because it had 3 elements in it), he was able to control relatively large changes of current with very small voltages. But! was it amplification? Remember, amplification is the process of taking a small signal and increasing its amplitude. In De Forest’s circuit, the small input signal was 3 volts dc. What De Forest got for an output 1-20 was a variation in plate current of 7.5 milliamperes. Instead of amplification, De Forest had obtained "conversion," or in other words, converted a signal voltage to a current variation. This wasn’t exactly what he had in mind. As it stood, the circuit wasn’t very useful. Obviously, something was needed. After examining the circuit, De Forest discovered the answer — Ohm's law. Remember E = I x R? De Forest wanted a voltage change, not a current change. The answer was simple: If you want and you have simply add E = I x R In other words, run the plate current variation (caused by the voltage on the grid) through a resistor, and cause a varying voltage drop across the resistor. This is shown in figure 1-16. 5 MILLIAMPERES 10 MILLIAMPERES 25 MILLIAMPERES Figure 1-16. — Operation of the plate load resistor. The circuit is identical to the one in figure 1-15 except that now a resistor (called a plate-load resistor, R L ) has been added to the plate circuit, and a voltmeter has been added to measure the voltage drop across R L . In view (A) of figure 1-16, the control grid is at 0 volts. Once again 5 milliamperes flow in the plate circuit. Now, the 5 milliamperes must flow through R L . The voltage drop is equal to: E = I x R E = (5 x 10 3 amperes) x (10 x 10 3 ohms) E = (5 x 10 3 ) x (10 x 10 3 ) E = 5x 10 E = 50 volts Thus the voltage drop across the plate-load resistor, R L , is 50 volts when no voltage is applied to the grid. In view (B) of the figure, +3 volts is applied to the control grid. Once again plate current increases to 10 milliamperes. The voltage drop across R L is 1-21 E = I x R E = (10 x 10 3 amperes) x (10 x 10 3 ohms) E = (10 x 10' 3 ) x (10 x 10 3 ) E = 10 x 10 E = 1 00 volts By applying +3 volts to the grid, the voltage drop across R L was increased by 50 volts (from the original 50 volts to 100 volts). In view (C), -3 volts has once again been applied to the control grid. Once again plate current decreases to 2.5 milliamperes, and the voltage drop across R L drops to 25 volts. We have caused the voltage across R L to vary by varying the grid voltage; but is it amplification? Well, let's take a look at it. The grid voltage, or input signal, varies from +3 to -3 volts, or 6 volts. The voltage drop across R L varies from 25 volts to 100 volts, or 75 volts. In other words, the triode has caused a 6- volt input signal (varying) to be outputted as a signal that varies by 75 volts. That's amplification ! Q13. What is the primary difference between a diode and a triode? Q14. Why does the grid have a greater effect than the plate on electron flow through a vacuum tube? Q15. What component is used in a triode amplifier to convert variation in current flow to voltage variation ? Let's summarize what you have learned so far: • A relatively small change in voltage on the grid causes a relatively large change in plate current. • By adding a plate-load resistor in series with the plate circuit, the changing plate current causes a changing voltage drop in the plate circuit. • Therefore, the small voltage change on the grid causes a large change of voltage in the plate circuit. • By this process, the small input signal on the grid has been amplified to a large output signal voltage in the plate circuit. We'll leave De Forest at this point. He showed that the control grid can, in fact, CONTROL plate current. He also showed that the changing plate current can create a changing plate voltage. To some degree, his changing voltages and currents also changed the world. INTRODUCTION TO GRID BIAS We purposely left out several features of practical triode circuits from the circuits we just discussed. We did so to present the idea of grid control more simply. One of these features is grid bias. Let's take another look at the circuit in figure 1-15 (B). We found that the positive charge on the grid caused more plate current to flow. However, when the grid becomes positive, it begins to act like a small plate. It draws a few electrons from the space charge. These electrons flow from the cathode across the gap to the positive grid, and back through the external grid circuit to the cathode. This flow is known as grid current. In some tube applications, grid current is desired. In others it is relatively harmless, while in some, grid current causes problems and must be eliminated. 1-22 Most amplifier circuits are designed to operate with the grid NEGATIVE relative to the cathode. The voltage that causes this is called a BIAS VOLTAGE. The symbol for the bias supply is E cc . One effect of bias (there are several other very important ones) is to reduce or eliminate grid current. Let’s see how it works. GRID BIAS is a steady, direct voltage that is placed at some point in the external circuit between the grid and the cathode. It may be in the cathode leg or the grid leg as shown in figure 1-17. It is always in series with the input signal voltage. In each of the circuits in figure 1-17, E cc makes the grid negative with respect to the cathode because of the negative terminal being connected toward the grid and the positive terminal being connected toward the cathode. With identical components, each circuit would provide the same bias. Figure 1-17. — Basic biasing of a triode. Battery bias is practically never used in modern circuits. Because of its simplicity, however, we will use it in analyzing the effects of bias. We will present other, more practical methods later. Let’s assume that the bias voltage in figure 1-17 is -6 volts. Let’s also assume that the peak-to-peak signal voltage from the transformer is 6 volts. Each of these voltage waveforms is shown in figure 1-18. From past experience you know that voltages in series ADD. Figure 1-18 has a table of the instantaneous values of the two voltages added together. The waveforms are drawn from these values. 1-23 TIME TIME 0 a b c d e f BIAS (Ec) -6 -6 -6 - 6 -6 - 6 - 6 SIGNAL (e g ) 0 +3 0 - 3 0 +3 0 TOTAL GRID VOLTS (Eg) -6 -3 -6 - 9 -6 - 3 - 6 Figure 1-18. — Typical grid waveforms. Because the bias voltage is more negative than the signal voltage is positive, the resultant voltage (bias plus signal), E g , is ALWAYS negative. The signal, in this case, makes the grid voltage go either MORE or LESS NEGATIVE, (-9 to -3) but cannot drive it positive. Under these circumstances, the negative grid always repels electrons from the space charge. The grid cannot draw current. Any problems associated with grid current are eliminated, because grid current cannot flow to a negative grid. You have probably already realized that the negative bias also reduces plate current flow. (Negative charge on grid-less plate current, right?) The trick here is for the circuit designer to choose a bias and an input signal that, when added together, do not allow the grid to become positive nor to become negative enough to stop plate current. Tube biasing is very important. You will learn much more about it shortly. From this brief introduction, you should have learned that grid bias • is a steady, direct voltage that in most cases makes the grid negative with respect to the cathode; • is in series with the signal voltage between grid and cathode; 1-24 • acts to reduce or eliminate grid current; • acts to reduce plate current from what it would be if no bias existed; • is produced in other ways than just by a battery; and • is important for reasons other than those just studied. OPERATION OF THE TRIODE The circuit in figure 1-19 brings together all of the essential components of a triode amplifier. Before analyzing the circuit, however, we need to define the term QUIESCENT. 0 E bb — VOLTAGE TABLE INPUT SIGNAL 6 VOLTS A.C. PE AK TO PE AK E bto 300 VOLTS D.C. POWER SUPPLY E cc -6 VOLTS D.C. BIAS BATTERY OUTPUT SIGNAL 100 VOLTS CHANGING D.C. UNDER QUIESCENT CONDRIONS (NO INPUT SIGNAL): E p = 200 VOLTS D.C. (PLATE VOLTAGE) Ip ■ 1 mA (PLATE CURRENT ASSUMED) INPUT SIGNAL = ZERO VOLTS GRID VOLTAGE = - 6 VOLTS ^ TIME ► Figure 1-19. — Triode operation. The term quiescent identifies the condition of a circuit with NO INPUT SIGNAL applied. With a given tube, bias supply, and plate supply, an exact amount of plate current will flow with no signal on the grid. This amount is known as the quiescent value of plate current. The quiescent value of plate voltage is the voltage between cathode and plate when quiescent current flows. 1-25 Simply, quiescent describes circuit conditions when the tube is not amplifying. The tube has no output signal and is in a kind of standby, waiting condition. Now let’s go on to figure 1-19. With no input signal, under quiescent conditions, assume that 1 milliampere of current flows through the tube, cathode to plate. This current (I p ) will flow through R L (load resistor) to the positive terminal of the battery. The current flowing through R L causes a voltage drop (IR) across R L equal to: E = Ip x R l E = lx 10 3 amperes x 100 x 10 3 ohms E = 100 volts Subtracting the voltage dropped across the plate-load resistor from the source voltage of 300 volts gives you 200 volts (300 volts - 100 volts). Thus, the plate voltage (E p ) is at 200 volts. The quiescent conditions for the circuit are: grid voltage = -6 volts plate voltage (Ep) = +200 volts These values are shown on the waveforms as time a in figure 1-19. You should notice that even though the grid is more negative (-6 volts) than the cathode, the tube in the circuit is still conducting, but not as heavily as it would if the grid were at zero volts. Now look at the input signal from the transformer secondary. For ease of explanation, we will consider only three points of the ac sine wave input: point b, the maximum negative excursion; point c, the maximum positive excursion; and point d, the zero reference or null point of the signal. At time b, the input signal at the grid will be at its most negative value (-3 volts). This will cause the grid to go to -9 volts (-6 volts + -3 volts). This is shown at time b on the grid voltage waveform. The increased negative voltage on the control grid will decrease the electrostatic attraction between the plate and the cathode. Conduction through the tube (I p ) will decrease. Assume that it drops to .5 milliamperes. The decrease in plate current will cause the voltage drop across the plate-load resistor (R L ) to also decrease from 100 volts, as explained by Ohm’s law: E = Ip x R l E = .0005 amperes x 100,000 ohms or E = (,5x 10' 3 amperes) x (100 x 10 3 ohms) E = 50 volts Plate voltage will then rise +250 volts. Ep = 300 volts - 50 volts = 250 volts ■ This is shown on the output signal waveform at time b. At time c, the input has reached its maximum positive value of +3 volts. This will decrease grid voltage to -3 volts (-6 volts + 3 volts). This is shown on the grid voltage waveform at time c. This in turn will increase the electrostatic force between the plate and cathode. More electrons will then flow from the 1-26 cathode, through the grid, to the plate. Assume that the plate current in this case will increase to 1.5 milliamperes. This will cause plate voltage (E b ) to decrease to 150 volts as shown below. E = Ip x Rl E = (1.5 x 10' 3 amperes) x (100 x 10 3 ohms) E = 150 volts Ep = 300 volts - 150 volts Ep = 150 volts This is shown on the output waveform at time c. At time d, the input signal voltage decreases back to zero volts. The grid will return to the quiescent state of -6 volts, and conduction through the tube will again be at 1 milliampere. The plate will return to its quiescent voltage of +200 volts (shown at time d on the output waveform). As you can see, varying the grid by only 6 volts has caused the output of the triode to vary by 100 volts. The input signal voltage has been amplified (or increased) by a factor of 16.6. This factor is an expression of amplifier VOLTAGE GAIN and is calculated by dividing the output signal voltage by the input signal voltage . Before going on to the next section, there is one more thing of which you should be aware. Look again at the waveforms of figure 1-19. Notice that the output voltage of the amplifier is 180° out of phase with the input voltage. You will find that this polarity inversion is a characteristic of any amplifier in which the output is taken between the cathode and the plate. This is normal and should not confuse you when you troubleshoot or work with this type of circuit. Q16. Why is the control grid of a triode amplifier negatively biased? Q17. For a circuit to be considered to be in the quiescent condition, what normal operating voltage must be zero ? Q18. A triode amplifier similar to the one shown in figure 1-19 has an -350 volts dc. The plate- load resistor is 50 kQ. Under quiescent conditions, 1.5 milliamperes of current conducts through the tube. What will be the plate voltage (E p ) under quiescent conditions? Q19. A 2-volt, peak-to-peak, ac input signal is applied to the input of the circuit described in Q18. When the signal is at its maximum positive value, 2.5 milliamperes flows through the tube. When the input is at its maximum negative value, conduction through the tube decreases to .5 milliamperes. a. What is the peak-to-peak voltage of the output signal? b. What is the phase relationship between the input and output signals? FACTORS AFFECTING TRIODE OPERATION The triode circuit you have just studied is a fairly simple affair. In actual application, triode circuits are a bit more complex. There are two reasons for this. The first has to do with the triodes ability to amplify and perform other functions. Triodes come in many different types. Each of these types has different internal characteristics and different capabilities. Because of this, each triode circuit must be designed to accommodate the triodes special characteristics. The second reason for the increase in 1-27 complexity has to do with DISTORTION. Distortion occurs in a tube circuit any time the output waveform is not a faithful reproduction of the input waveform . Polarity inversion and voltage gain of the output waveform are not included in this definition of distortion. Some circuits are designed to distort the output. The reason and methods for this deliberate distortion will be covered in a later NEETS module. For the most part, however, we desire that circuits eliminate or reduce distortion. Because the grid is close to the cathode, small changes in grid voltage have large effects on the conduction of triodes. If a large enough input signal is placed on the grid, a triode may be driven into either plate-current cutoff or plate -current saturation. When this occurs, the tube is said to be OVERDRIVEN. Overdriving is considered to be a form of DISTORTION. Look at time zero (0) in the waveforms of figure 1-20. The input signal (E in ) is at zero volts. Grid voltage equals the bias voltage (-6 volts), and one milliampere of current is flowing through the tube (quiescent state). Plate voltage (E p ) is 200 volts. INPUT GRID VOLTAGE (BIAS + SIGNAL) OUTPUT SIGNAL VOLTAGE TABLE E |N INPUT SIGNAL 50 VOLTS PEAK TO PEAK E bb PLATE SUPPLY + 300 VOLTS D.C E cc BIAS SUPPLY -6 VOLTS D.C. e OUT OUTPUTS,GNAL 200 VOLTS PE AK TO PEAK E p AT CUTOFF + 300 VOLTS D.C. E p AT SATURATION + 100 VOLTS D.C Figure 1-20. — Overdriven triode. On the negative half of the input signal, the grid voltage is made more negative. This reduces plate current which, in turn, reduces the voltage drop across R L . The voltage between cathode and the plate is thereby increased. You can see these relationships by following time "a" through the three waveforms. 1-28 Now, let’s assume that this particular triode cuts plate current flow off when the grid reaches -24 volts. This point is reached at time b when E in is -18 and the bias is -6 (-18 and -6 = -24). Plate current remains cut off for as long as the grid is at -24 volts or greater. With zero current flowing in the plate circuit, there is no voltage drop across R L . The entire plate- supply voltage, E bb (300 volts), appears as plate voltage between the cathode and the plate. This is shown at time b in the output signal waveform. Between time b and time c, the grid voltage is greater than -24 volts. The plate current remains cutoff, and the plate voltage remains at +300. The output waveform between time b and time c cannot follow the input because the plate voltage cannot increase above +300 volts. The output waveform is "flattopped." This condition is known as AMPLITUDE DISTORTION. When the grid voltage becomes less negative than -24 volts, after time c, the tube starts conducting, and the circuit again produces an output. Between time c and time d, the circuit continues to operate without distortion. At time e, however, the output waveform is again distorted and remains distorted until time f. Let’s see what happened. Remember that every cathode is able to emit just so many electrons. When that maximum number is being emitted, the tube is said to be at SATURATION or PLATE SATURATION. Saturation is reached in a triode when the voltages on the grid and plate combine to draw all the electrons from the space charge. Now, as our grid becomes less negative (between time c and time d), and actually becomes positive (between time d and time e), the plate current increases, the voltage across R L increases, and the plate voltage decreases. Apparently when the grid voltage reached +12 volts at time e, the plate current reached saturation. Maximum plate current (at saturation) results in maximum voltage across R L and minimum plate voltage. Any grid voltage higher than +12 volts cannot cause further changes in the output. Therefore, between time e and time f, the plate voltage remains at +100 volts and the waveform is distorted. This is also AMPLITUDE DISTORTION. This has been an explanation of one cycle of an input signal that overdrives the tube. You should notice that, using the same circuit, a 50-volt peak-to-peak input signal caused a vastly different output from that caused by the 6-volt peak-to-peak input signal. The 6-volt peak-to-peak signal did not overdrive the tube. When the input signal was increased to 50-volts peak-to-peak, the tube was forced into cutoff when the grid was driven to -24 volts, and into saturation when the grid was driven to +12 volts (the grid voltage plus the signal voltage.) During these periods, the tube could not respond to the input signal. In other words, the output was distorted. A method commonly used to partially overcome distortion is to vary the bias voltage on the grid. The point at which the tube goes into cutoff or saturation can then be controlled. For this reason tube biasing is of great importance in most tube circuits. 1-29 020 . The waveforms shown below are the input and output of an overdriven triode. INPUT a. Distortion A at the output is the result of what condition? b . Distortion B at the output is the result of what condition? TYPES OF BIASING There are two main classes of biasing — FIXED and SELF. In a tube circuit that uses fixed bias, the grid-bias voltage is supplied from a power source external to the circuit. You are already familiar with battery bias, which is one form of fixed bias. When fixed bias is used in a circuit, it can be represented as either a battery (fig. 1-21, view A), or as a conductor connected to -E cc (fig. 1-21, view B). Fixed bias is rarely used in electronics today. Therefore, we will not discuss it further. SIGNAL E cc (B) Figure 1-21. — Fixed bias: A. Battery B. Conductor In circuits using self-bias, the bias voltage is developed across a resistor in the cathode or grid circuit by tube current. There are two main methods of self-bias: cathode biasing and grid-leak biasing. Cathode Bias In circuits using cathode bias, the cathode is made to go positive relative to the grid. The effect of this is the same as making the grid negative relative to the cathode. Because the biasing resistor is in the cathode leg of the circuit, the method is called CATHODE BIASING or CATHODE BIAS. A triode circuit using cathode bias is shown in figure 1-22. 1-30 Figure 1-22. — Cathode bias. The only difference between the illustrated circuit and the one used to demonstrate triode operation is the elimination of the battery, E cc , and the addition of circuit components R k , the cathode-biasing resistor; C k , the cathode ac -bypass capacitor; and a grid resistor (whose purpose will be explained later). When the tube conducts, current flows from the battery through R k to the cathode, through the tube to the plate, and through R L to the positive terminal of the battery. The current flowing through R k will cause a voltage drop across R k . The bottom of R k goes negative while the top goes positive. This positive voltage at the top of R k makes the cathode positive relative to the grid. You may wonder what purpose C k serves in this circuit. C k serves as an AC BYPASS. Without C k , the bias voltage will vary with ac input signals. This is particularly troublesome in the higher frequencies like those found in radio receivers. R k , the cathode-biasing resistor, is used to develop the biasing voltage on the cathode. The input signal will be developed across R g . You will read more about the circuit component later in this chapter. Cathode-biasing voltage is developed in the following manner. As we mentioned earlier, the bias voltage will vary with the input unless C k , the cathode bypass capacitor, is used. To understand how the bias voltage will vary with an ac input signal, disregard C k for the moment and refer to figure 1-22 again. Notice that under quiescent conditions, the voltage drop at the top of R k is +10 volts. Now let’s apply the positive-going signal illustrated to the left of the tube. When the positive signal is applied, conduction through the tube will increase. The only trouble is that current through R k will also increase. This will increase the voltage drop across R k , and the cathode voltage will now be greater than +10 volts. Remember, at this time the plate is going negative due to increased conduction through the tube. The combination of the negative-going plate and the positive-going cathode will decrease the electrostatic attraction across the tube and lower the conduction of the tube. This will reduce the gain of the tube. When the negative-going signal is applied, conduction through the tube decreases. Current through R k decreases and the voltage drop across R k decreases. This causes the cathode to go more negative, which tends to increase conduction through the tube. A negative-going signal is amplified by decreasing plate current and allowing the plate to go positive (remember the 180° inversion.) Thus, increasing 1-31 conduction on the negative half-cycle decreases the gain of that half-cycle. The overall effect of allowing cathode biasing to follow the input signal is to decrease the gain of the circuit with ac inputs. This problem can be overcome by installing C k . The purpose of C k is to maintain the cathode bias voltage at a constant level. In common usage, the action of C k is referred to as "bypassing the ac signal to ground." The action of C k will be explained using figure 1-23. View A shows the circuit under quiescent conditions. With some conduction through the tube, the cathode and the tops of R k and C k are at +10 volts. Figure 1-23. — Effect of the bypass capacitor. In view B, the positive-going signal is applied to the grid. This causes increased conduction through the tube, which attempts to drive the cathode to +20 volts. But notice that the top of C k is still at +10 volts (remember capacitors oppose a change in voltage). The top plate of C k is, in effect, 10 volts negative in relation to the top of R k . The only way that C k can follow the signal on the top of R k (+20 volts) is to charge through the tube back to the source, from the source to the lower plate of C k . When C k charges through the tube, it acts as the source of current for the cathode. This causes the cathode to remain at +10 volts while the capacitor is charging. View C of the figure shows the same signal. Under these conditions, conduction through R k will decrease. This will cause a decrease in current flow through R k . Decreased current means decreased voltage drop. The top of R k will try to go to +5 volts. C k must now go more negative to follow the top of R k . To do this, current must flow from C k through R k , to the top plate of C k . This discharging of C k will increase current flow through R k and increase the voltage drop across R k , forcing the top to go more positive. Remember, the voltage drop is due to current flow through the resistor. (The resistor could care less if the current is caused by conduction or capacitor action.) Thus, the cathode stays at +10 volts throughout the capacitor-charge cycle. There is one point that we should make. C k and R k are in parallel. You learned from previous study that voltage in a parallel circuit is constant. Thus, it would seem impossible to have the top of R k at one voltage while the top plate of C k is at another. Remember, in electronics nothing happens instantaneously. There is always some time lag that may be measured in millionths or billionths of seconds. The action of C k and R k that was just described takes place within this time lag. To clarify the explanation, the voltages used at the components R k and C k were exaggerated. Long before a 10-volt differential could exist between the tops of R k and C k , C k will act to eliminate this voltage differential. 1-32 The capacitor, then, can be said to regulate the current flow through the bias resistor. This action is considered as BYPASSING or eliminating the effect of the ac input signal in the cathode. For all practical purposes, you can assume that ac flows through the capacitor to ground. But, remember, ac only appears to flow across a capacitor. In reality the ac signal is shunted around the capacitor. There are two disadvantages associated with cathode biasing. To maintain bias voltage continuously, current must flow through the tube, and plate voltage will never be able to reach the maximum value of the source voltage. This, in turn, limits the maximum positive output for a negative input signal (remember the 180° inversion). In addition, maximum plate voltage is decreased by the amount of cathode-biasing voltage. What this means is that you can't get something for nothing. If the cathode is biased at +20 volts, this voltage must be subtracted from the plate voltage. As an example, consider a triode with a 10,000 ohm plate resistor and a +300 volts dc source voltage. If a current of 2 milliamperes flows through the tube under quiescent conditions, 20 volts are dropped across the plate-load resistor. The maximum plate voltage is then 300 volts - 20 volts = 280 volts dc. Now, consider the 20-volt dropped across the cathode resistor. Plate voltage becomes 280 volts - 20 volts = 260 volts. To understand this a little more thoroughly, look at figure 1-24. In view A, the source voltage is 300 volts dc. There are two ways that this voltage can be looked at; either the plate is at +300 volts and the cathode is at 0 volts (ground), or the plate is at +150 volts and the cathode is at -150 volts. In electronics, it is common practice to assume that the plate is at +300 volts while the cathode is at 0 volts. To simplify this discussion, we will assume that the plate is at +150 volts, and the cathode is at -150 volts. The potential difference between the plate and the cathode is 300 volts. If a plate-load resistor is installed, as shown in view B, 20 volts are dropped by R L . The potential difference between the plate and the cathode is now 280 volts. In view C, R k has now been placed in the same circuit. R k drops 20 volts. Therefore, the effect of cathode biasing is to reduce the maximum positive signal that the circuit can produce. In this case, the maximum positive signal has been reduced by 20 volts. Despite these disadvantages, cathode biasing has two main advantages. It is simple and economical. (A) (B) (C) Figure 1-24. — Loss due to cathode biasing. Grid-Leak Biasing The second type of self-biasing to be discussed is GRID-LEAK BIAS. As the name implies, bias voltage is developed in the grid leg portion of the circuit. Bias voltage in this type of biasing is derived by allowing the positive input signal to draw grid current through a circuit made up of a resistor and a capacitor. There are two types of grid-leak bias commonly in use: SHUNT TYPE and SERIES TYPE. Because shunt type grid-leak biasing is the simplest, we will discuss it first. Figure 1-25 depicts a simplified triode circuit using the shunt-type grid-leak biasing. Before we begin the explanation of shunt 1-33 grid-leak biasing, there is one thing you should bear in mind. Because the bias is derived from the positive input signal through capacitive action, the input signal must go through several positive alternations before the final operating bias voltage is achieved. We will explain why this is so in the following discussion. View A of figure 1-25 shows the circuit under quiescent conditions. You will notice that the circuit is similar to the one we used to explain the action of a triode. The only additions are the grid resistor, R g coupling capacitor, C c , and resistance rgk. Resistance rgk doesn’t exist as a physical component, but it is used to represent the internal tube resistance between the triode’s cathode and grid. Electrically, rgk is quite small, about 500 ohms. Under quiescent conditions, some conduction occurs through the tube. Some electrons will strike the wires of the grid, and a small amount of GRID CURRENT will flow through R g to ground. This will cause the right-hand plate of C c to go slightly negative. This slight negative charge will, in turn, keep the grid of the tube slightly negative. This limits the number of electrons that strike the grid wires. CHARGE CIRCUIT (B) DISCHARGE CIRCUIT Figure 1-25. — Shunt grid-leak biasing. In view B of the figure, the first positive alternation of a series of ac alternations, E in is applied to the circuit. The positive-going voltage causes the left-hand plate of C c to go positive. The left-hand plate must lose electrons to go positive. These electrons leave the left-hand plate of C c and travel to the input source where they will be coupled to ground. From ground, current flows through R g causing a negative (bottom) to positive (top) voltage drop across R g . In effect, the ac signal has been coupled across the capacitor. Because of this, capacitors are said to pass the ac signal while blocking dc. (In reality, the ac signal is coupled around the capacitor.) In view C of the figure, the positive-going voltage at the top of R g will be coupled to the grid causing the grid to go positive. The positively charged grid will attract electrons from the electron stream in the tube. Grid current will flow from the grid to the right-hand plate of C c . This will cause the right-hand plate to go negative. (Electrostatic repulsion from the right-hand plate of C c will force electrons from the left-hand plate of C c , causing it to go positive.) The electrons will flow through the signal source, to ground, from ground to the cathode, from the cathode to the grid, and finally to the 1-34 right-hand plate of C c . This is the biasing charge cycle . You may wonder why the charge current went through the tube rather than through R g . When the grid goes positive in response to the positive-going input signal, electrostatic attraction between the grid and cathode increases. This, in turn, reduces the resistance (rgk) between the grid and cathode. Current always follows the path of least resistance. Thus, the capacitor charge path is through the tube and not through R g . When the first negative alternation is applied to the circuit (view D), the left-hand plate of C c must go negative. To do this, electrons are drawn from the right-hand plate. The electrons travel from the right-hand plate of C c , through R g causing a voltage drop negative (top) to positive (bottom), from the bottom of R g , through the source, to the left-hand plate of C c . C c will discharge for the duration of the negative alternation. BUT C c can only discharge through R g , which is a high-resistance path, compared to the charge path. Remember from your study of capacitors that RC time constants and the rate of discharge increase with the size of R. C c can therefore charge through the low resistance of rgk to its maximum negative value during the positive half-cycle. Because C c discharges through R„ (the high resistance path), it cannot completely discharge during the duration of the negative half-cycle. As a result, at the completion of the negative alternation, C c still retains part of the negative charge it gained during the positive alternation. When the next positive alternation starts, the right-hand plate of C c will be more negative than when the first positive alternation started. During the next cycle, the same process will be repeated, with C c charging on the positive alternation and discharging a lesser amount during the negative alternation. Therefore, at the end of the second cycle, C c will have an even larger negative charge than it did after the first cycle. You might think that the charge on C c will continue to increase until the tube is forced into cutoff. This is not the case. As the negative charge on the right-hand plate of C c forces the grid more negative, electrostatic attraction between the grid and cathode decreases. This, in effect, increases the resistance (rgk) between the cathode and the grid, until rgk becomes, in effect, the same size as R g . At this point, charge and discharge of C c will equal one another and the grid will remain at some negative, steady voltage. What has happened in this circuit is that C c and R g , through the use of unequal charge and discharge paths, have acted to change the ac input to a negative dc voltage. The extent of the bias on the grid will depend on three things: the amplitude of the input, the frequency of the input, and the size of R< r and C c . This type of biasing has the advantage of being directly related to the amplitude of the input signal. If the amplitude increases, biasing increases in step with it. The main limiting factor is the amount of distortion that you may be willing to tolerate. Distortion occurs during the positive alternation when the grid draws current. Current drawn from the electron stream by the grid never reaches the plate; therefore the negative-going output is not a faithful reproduction of the input, while the positive-going output (during the negative input cycle) will be a faithful reproduction of the input. This is similar to the situation shown in the flattopped portion of the output signal in figure 1-20. The SERIES GRID-LEAK BIAS circuit shown in figure 1-26 operates similarly to the shunt grid- leak circuit. When the first positive alternation is applied to the left-hand plate of the grid capacitor, C g , the left-hand plate must lose electrons to go positive with the input. Electrons will leave the left-hand plate and flow through R g , causing a negative (left-hand side) to positive (right-hand side) voltage drop. From the right-hand side of R g , the electrons will flow to the right-hand plate of C g . The positive voltage developed at the right-hand side of R g will be coupled to the grid. As the grid goes positive, it will draw current, causing C g to start to charge through the low resistance path of the tube. During the negative alternation of the input, C g will discharge through the high resistance path of R g . Once again it will not be completely discharged at the end of the negative alternation, and the capacitor will continue on its way toward charge equilibrium. 1-35 Figure 1-26. — Series grid-leak biasing. In summary, grid-leak bias causes the grid to draw current when the input signal goes positive. This grid current (which is a negative charge) is stored by the coupling capacitor (C c ,) which will keep the grid at some negative potential. It is this potential that biases the tube. Q21. What type of bias requires constant current flow through the cathode circuit of a triode? Q22. When a circuit uses cathode biasing , the input signal can cause variations in the biasing level How is this problem eliminated? Q23. In a circuit using grid-leak biasing, the coupling capacitor ( C c ) charges through a low resistance path. What resistance is used in this charge path? Q24. Grid-leak biasing in effect rectifies the input ac signal. What feature of the circuit is used to accomplish this rectification ? OPERATING CLASSIFICATIONS OF TUBE AMPLIFIERS While the discussion of amplifiers will be covered in detail in later NEETS modules, some discussion of the classes of operation of an amplifier is needed at this point. This is because their operation class is directly determined by the bias voltage of the tube. The classification of amplifiers by operation is based on the percentage of the time that the tube conducts when an input signal is applied. Under this system amplifiers may be divided into four main classes: A, AB, B, and C. CLASS A OPERATION An amplifier biased into Class A operation, is one in which conduction through the tube occurs throughout the duration of the input signal. Such an amplifier is shown in figure 1-27, view A. This is the same type of circuit with which you are already familiar. Notice when you compare the input to the output that the tube is always conducting, and that the entire input signal is reproduced at the output. 1-36 + E bb ' 100 % REFERENCE + E bb OC-9-5V INPUT CUTOFF ^reference 100 % - 50 % Figure 1-27. — Classes of amplifier operation. CLASS AB OPERATION The Class AB amplifier is one in which the tube conducts for more than half, but less than the entire input cycle. View B of figure 1-27 depicts an amplifier biased into CLASS AB operation. Notice that in this application, grid bias has been increased to -9 volts. We will assume that the tube reaches cutoff when the voltage on the grid is -10 volts. Under these conditions, when the input reaches -10 volts, the tube will cut off and stay cut off until the input goes above -10 volts. The tube conducts during the entire duration of the positive alternation and part of the negative alternation. If you remember back in the discussion of distortion, we pointed out that this represents distortion. In some amplifiers, faithful reproduction of the input is not an important requirement. Class AB amplifiers are used only where this distortion can be tolerated. CLASS B OPERATION A CLASS B biased amplifier is one in which the tube will conduct for only half of the input signal duration. This is done by simply biasing the amplifier at cutoff. View C of figure 1-27 depicts a class B biased amplifier. As you can see, the tube conducts on the positive alternations. As soon as the input signal voltage reaches 0 volts, the tube cuts off. The tube will remain cut off until the input signal voltage climbs above zero volts on the next positive alternation. Because the tube conducts during the entire positive alternation, but not on the negative alternation, the tube conducts for only half the input cycle duration. 1-37 CLASS C CLASS C amplifiers are biased below cutoff, so that the tube will conduct for less than half of the input signal cycle duration. View D of figure 1-27 depicts a Class C amplifier. Notice that the tube is biased one-half volt below cutoff. The tube will only conduct on that part of the positive alternation that is above +.5 volts. Therefore, the tube conducts for less than one -half cycle of the input. Again, this class can be applied only where severe distortion can be tolerated. TUBE CONSTANTS In the discussion of triodes, we only considered the effects of the external circuit on the passage of current through the tube. The behavior of the electron stream in a conducting tube is also influenced by the physical structure of the tube. The effects that the physical structure of a tube has on the tube’s operation are collectively called TUBE CONSTANTS. Four of the most important of these tube constants are: TRANSIENT TIME, INTERELECTRODE CAPACITANCE, TRANSCONDUCTANCE, and AMPLIFICATION FACTOR. TRANSIT TIME Unlike electron flow in a conductor, electrons in a vacuum tube do not move at the speed of light. Their velocity is determined by the potential difference between the plate and the cathode. The amount of time the electrons take to travel from the cathode to the plate is called TRANSIT TIME. As a result of this time difference, the appearance of a signal at the end of a tube is not followed instantaneously by a change in current flow in the tube. Under normal conditions, the effect of this small time lag between the input signal and a change in tube current is unnoticed. However, at frequencies such as those used in radar equipment, this is not the case. Transit time at these frequencies has a very marked effect on tube operation. It is a major factor that limits the use of a given tube at higher frequencies. Q25. Match each amplifier characteristic listed below with its class of amplification. a. Current flows through the tube for one -half cycle. b. Current flows through the tube for less than one-half cycle. c. Current flows through the tube for the entire cycle. MU AND TRANSCONDUCTANCE In your study of triodes so far, you have seen that the output of a triode circuit is developed across the tube. The output is caused by the voltage dropped across R L due to current flow from tube conduction. In all the demonstrations of gain, we assumed that R L was held constant and current through the tube was varied. In this manner we achieved a voltage gain. If the resistance of R L is changed by the designer, the gain of a triode circuit can be either increased or decreased. This is fairly easy to understand. Assume that a circuit is composed of a triode with a plate-load resistor of 100 kohms. If a +2 volt signal causes 2 additional milliamperes to conduct through the tube, the voltage drop across R L (the output) will be: 1-38 E = I x R E = Ip x Rl E = (2x 10' 3 amperes) x (100 x 10 3 ohms) E = 2 x 100 volts E = 200 volts Gain = Gam = output input 200 volts 2 volts Gain = 100 Thus, the gain of the circuit is 100. If the plate -load resistor is reduced to 50 kohms and the input is kept at +2 volts, the gain will be reduced to: E = (2x 10' 3 amperes) x (50 x 10 3 ohms) E = 2 x 50 volts E = 100 volts Gain = 100 volts 2 volts Gam = 50 As you can see, voltage gain depends on both the tube characteristics and the external circuit design. The voltage gain is a measure of circuit efficiency, not tube efficiency. The actual characteristics of a tube are measured by two factors: mu(p) or AMPLIFICATION FACTOR; and TRANSCONDUCTANCE or g m . The amplification factor (represented as p) of a tube is equal to the ratio of a change in plate voltage to the change in grid voltage required to cause the same change in plate current. This is expressed mathematically as While this may sound complicated, it really isn't. Look at figure 1-28. Here you see in view A a triode with a +1 volt input signal. At this grid voltage, current through the tube is at 1 milliampere. If the input voltage is raised to +3 volts, current through the tube increases to 2 milliamperes. The change in E g (AE g ) is then 2 volts. This is shown in view B. Suppose that the grid voltage is returned to +1 volt, and the plate voltage is increased until the ammeter in view C reads 2 milliamperes of plate current. At this point plate voltage is measured. Plate voltage had to be increased by 100 volts (350-250) to get the same change in plate current (1 mA). The change in plate voltages (AE P ) is then 100 volts. The amplification factor (ji) of just the tube is then equal to 1-39 AE AE P g _ 100 volts ^ 2 volts pi = 50 + E bb + E bb +E bb (A) - (B) - (C) - Figure 1-28. — Obtaining gain and transconductance. As you can see, mu is a measure of the ability of a tube to amplify. By comparing the mu of two different types of tubes, you can get an idea of their efficiency. For example, assume you have two different tubes, one with a mu of 50, and the other with a mu of 100. If you place each tube in a circuit whose input varies by 2 volts, you can expect the following changes in plate voltage. Tube 1: AE p =jtx AE g AE p = 50 x 2 volts AE p = 100 volts 1-40 Tube 2: AE p =jt x AE g AE p = 100 x 2 volts AEp = 200 volts Thus, you can expect twice the change in plate voltage from tube 2 as from tube 1 for the same input voltage. Therefore, tube 2 will have twice the gain of tube 1. T ransconductance Transconductance is a measure of the change in plate current to a change in grid voltage, with plate voltage held constant. The unit for conductance is the mho (siemens), pronounced "moe." Transconductance is normally expressed in either micromhos or millimhos. Mathematically, transconductance is expressed by the formula: Examine figure 1-28, views A and B, again. In view A, the input voltage is +1 volt. At +1 volt E g , the plate current is equal to 1 milliampere, with a plate voltage of 250 volts. In view B, the input voltage (Eg) is raised to +3 volts. AE g , as before, is equal to 2 volts. This increase in grid voltage causes plate current to increase to 2 milliamperes. The change in plate current (AI P ) is then equal to 1 milliampere. Thus, transconductance (g m ) is equal to: 1 milliampere 2 volts gm =.5millimho or 500 ^mhos Remember that the voltage gain of a circuit is measured by the ratio of the change in plate voltage to the change in grid voltage. Because plate voltage is developed across a resistor, the more current varies with a given input signal, the greater will be the output (E = I x R). If you have two tubes, one with a gm of 500 mhos and the other with a gm of 500 jxmhos, you can estimate the relative gain of these two tubes. Assume that the circuit in which you wish to use one of these tubes has a load resistor of 100 kohms and that AE g will be 2 volts. The voltage gain of these two circuits will be: 1-41 Tube 1: Tube 2: AI p = AE g xgn AI p = 2x,5 millmho Alp =lmilliampere AEp - -AIp x Rl AE p = (1 x 10 -3 ampere) x (100 x 10 3 ohms) AEp =100 volts Gam = output input Gam = 100 volts 2 volts AIp = AE g xgn AIp = 2 volts x 5 millmho AIp =10 milliampere AEp - AIp x R l AE p =(10xl0 -3 ampere) x (100 xlO 3 ohms) AEp = 1000 volts Gain = output input Gam = 1000 volts 2 volts 1-42 As you can see, tube 2 is 10 times the amplifier that tube 1 is. Q26. The plate voltage of a tube will vary 126 volts when a 3-volt ac signal is applied to the control grid. What is the gain of this tube? Q27. If the mu of a tube is 85 and the signal at the control grid is 4 volts ac, the plate voltage will vary by what amount? Q28. Transconductance is a measure of the relationship between what two factors? Q29. A tube has a transconductance of 800 mhos and a load resistor of 50 kohms. When control grid voltage varies by 6 volts, the plate voltage will vary by what amount? INTERELECTRODE CAPACITANCE As you know, capacitance exists when two pieces of metal are separated by a dielectric. You should also remember from your studies that a vacuum has a dielectric constant of 1. As the elements of the triode are made of metal and are separated by a dielectric, capacitance exists between them. This capacitance is called interelectrode capacitance , and is schematically represented in figure 1-29. Figure 1-29. — Schematic representation of interelectrode capacitance. Notice that there are three interelectrode capacitances involved in a triode. The capacitance between the plate and grid, designated C pg , is the largest, because of the relatively large area of the plate, and therefore has the greatest effect on triode operation. The grid-to-cathode capacitance is designated C kg . The total capacitance across the tube is designated C pk . As we said earlier, C pg has the greatest effect on the tube operation. This is because this capacitance will couple part of the ac signal from the plate back to the grid of the tube. The process of coupling the output of a circuit back to the input is called FEEDBACK. This feedback affects the gain of the stage. It may be desirable in some applications. In others, the effects must be neutralized. The effects of C pk are greater at higher frequencies where X c is lower. 1-43 DEVELOPMENT OF THE TETRODE Interelectrode capacitance cannot be eliminated from vacuum tubes, but it can be reduced. The easiest method found to reduce interelectrode capacitance is to split the capacitance between the grid and plate (C pg ) into two capacitors connected in series. This is done by placing an extra grid, called the SCREEN GRID, between the control grid and the plate. This is shown in figure 1-30. CONTROL GRID ( 0 .) Figure 1-30. — Effect of the screen-grid on Interelectrode capacitance. Remember from your study of capacitance that connecting capacitors in series reduces the total capacitance to a value smaller than either of the capacitors. This is mathematically summed up as follows: Cl x C2 C1 + C2 The addition of the screen grid has the effect of splitting C pg into two capacitances (Cl and C2) connected in series. Therefore, the total interelectrode capacitance between the control grid and the plate is greatly reduced. OPERATION OF THE BASIC TETRODE CIRCUIT Figure 1-31 depicts a basic tetrode circuit. While the circuit may look complicated, it isn’t. You are already familiar with most of the circuit. Only three components have been added: the screen grid, the screen grid dropping resistor, and the screen grid bypass capacitor (C sg ). 1-44 Figure 1-31. — Basic tetrode circuit. The problem now is: at what voltage and polarity should the screen grid be operated? If the screen grid were operated at a potential that would make it negative in relation to the control grid, it would act as a negative screen between the plate and control grid. As a result, gain would be reduced. If the screen grid were operated at plate potential, it would draw current from the electron stream when the tube conducts. Because of this, the value of R sg is normally selected to cause the screen grid to be positive in relation to the control grid, but not as positive as the plate. Despite this precaution, the screen grid still draws some current from the electron stream. Any signal applied to the control grid will appear at the screen grid inverted by 180° from the input signal. This is undesirable, as it reduces the gain of the tube. Consider the effect if the control grid goes positive. Conduction through the tube increases, and since the screen grid is in the electron stream, it will draw some current. This causes the screen grid to go toward negative potential (less positive). The effect then, is to place a negative-going electrode between the plate and positive-going control grid. The plate becomes partially screened by the negative-going screen grid, and again, gain will decrease. Because the signal at the screen grid is always 180° out of phase with the control grid, its effect will always be to oppose the effect of the control grid. To overcome this, a bypass capacitor (C sg ) is connected between the screen grid and ground. The addition of this capacitor will shunt, or pass, the ac variations on the screen grid to ground while maintaining a steady dc potential on the screen grid. In other words, C sg moves all of the undesired effects mentioned in the previous paragraph. One very useful characteristic of the tetrode tube is the relationship between the plate and screen grid. The screen grid will lessen the effect that a decreasing plate potential (negative-going signal) has on conduction through the tube. In a triode, when the grid goes positive, the plate goes negative. This decreases electrostatic attraction across the tube and tends to decrease the gain somewhat. In a tetrode, the screen grid has the ability to isolate the effect that ac variations on the plate have on the electron stream. The positively charged screen grid will accelerate electrons across the tube even though the plate is negative going. As long as the plate remains positive in relation to the cathode, it will draw off these accelerated electrons. As a result, conduction through the tube when the plate is going negative will not be decreased. This is another big advantage of screen-grid tubes. 1-45 TETRODE CHARACTERISTICS Because the screen grid is in the electron stream, it will always draw some current. The current drawn by the screen grid will be lost to the plate. This means that the transconductance of a tetrode, which is based on the amount of plate current versus control-grid voltage, will be lower in tetrodes than in triodes. The formula for transconductance of a triode, must be adjusted for screen-grid current, and becomes As you can see, the transconductance for a tetrode can never be as high as that of a triode of similar construction. While lowered transconductance in a tetrode is an undesirable characteristic, it is not the reason that tetrodes have found little acceptance in electronics. The factor that severely limits the operation of tetrodes is SECONDARY EMISSION. Because the screen grid is positively charged, electrons traveling from the cathode to the plate are accelerated. Electrons are accelerated to such an extent that they dislodge electrons from the plate when they strike it. This is similar to the manner in which a high-velocity rifle bullet fired into a pile of sawdust throws sawdust about. Some of these electrons are fired back into the tube, where they tend to accumulate between the screen grid and the plate. This effect is most pronounced when the signal at the control grid is going positive and conduction through the tube is increasing. The plate in this situation is going negative in answer to the control-grid signal. This causes the electrons accumulating between the plate and screen grid to be attracted to the screen grid. The current that is drawn by the screen grid is lost to the plate and gain is decreased. Gain is also decreased in another way. The negative charge accumulated by secondary emission causes some of the electrons (from the cathode) to be repelled from the plate, which further reduces gain. Another undesirable characteristic of tetrodes associated with secondary emission is that the outputs are NOISY. What this means is that small sporadic signals appear on the main output signal, as shown in figure 1-32. When electrons are knocked from the plate, they represent losses of plate current and corresponding positive pulses on the output. Electrons falling back to the plate represent increases in plate current and cause negative-going pulses to appear in the output. 1-46 + E bb + E bb TRIODE TETRODE Figure 1-32. — Noise in a tetrode circuit. For these reasons tetrodes are only used in very specialized applications of electronics. Q 30. How does the addition of a screen grid in a tetrode reduce interelectrode capacitance? Q31. What undesirable effect does the screen grid in a tetrode create? THE PENTODE The problem of secondary emission associated with the screen grid of a tetrode has been reduced by — you guessed it, the addition of another grid. This third grid, called a SUPPRESSOR GRID, is placed between the screen grid and the plate. The suppressor grid is normally connected either internally or externally to the cathode and bears the same charge as the cathode. This is shown in figure 1-33. Because of its negative potential (relative to individual electrons), any electrons that are emitted by the plate, through secondary emission, are repelled back toward the plate. Figure 1-33. — Basic pentode circuit. 1-47 You might think that a grid with a negative potential placed close to the plate would interfere with the electron stream. However, this is not the case. Because the suppressor grid is negatively charged, it will not draw grid current. Additionally, the wide spacing within the mesh of the suppressor and its location between two positive elements of the tube ensures that the suppressor grid’s effect on the electron stream will be minimum. Only the electrons emitted by secondary emission from the plate are affected by the suppressor grid. Because pentodes do not suffer from secondary emission, they have replaced the tetrode in most applications. Q32. The suppressor grid is added to a tetrode to reduce what undesirable characteristic of tetrode operation? Q33. On the diagram below , name the elements of the vacuum tube and their potentials relative to dc ground. SUMMARY This chapter has introduced you to the four basic types of vacuum tubes. The following is a summary of the main points of the chapter. THERMIONIC EMISSION is caused when metallic substances are heated to high temperatures. Electrons liberated by thermonic emission provide the conduction currents of vacuum tubes. A DIODE VACUUM TUBE is composed of two elements: the cathode and the plate. 1-48 AMMETER- METAL PLATE GAP FILAMENT + The CATHODE is the electron-emitting element of a tube. Cathodes are usually composed of special materials that are heated either directly or indirectly. / n SUPPORT — FILAMENT DIRECTLY HEATED SCHEMATIC CONSTRUCTION DIODE OPERATION depends upon current flow through the tube. Because the cathode is the only electron-emitting element in the tube, current can only flow in one direction, from the cathode to the plate. For current to flow, the plate must be positive relative to the cathode. When the plate is negative relative to the cathode, current cannot flow within the tube. 1-49 AMMETER J" 41 * + E bb SUPPLY The CHARACTERISTIC CURVE for an electron tube is a graphic plot of plate current (I p ) versus plate voltage (E p ). From this, dc plate resistance can be computed by the formula: FACTORS THAT LIMIT VACUUM TUBE OPERATION are plate dissipation, maximum average current, maximum peak-plate current, and peak-inverse voltage. DIODE RECTIFIERS take advantage of the fact that diodes will conduct in only one direction. When ac voltages are applied to diodes, conduction occurs only on the alternation that makes the plate positive relative to the cathode. Because of this, the output current consists of one polarity. Because it flows in pulses rather than continuously, it is called pulsating dc. Esec Epri Ip DIODE CONSTRUCTION is the basic construction plan of most vacuum tubes. The tube is constructed of the following parts: filament and/or cathodes, plates, envelope, and base. 1-50 The OPERATION OF A TRIODE depends on the ability of the control grid to either increase or decrease conduction through the tube in response to an ac input signal. The output voltage is developed across the tube between the cathode and plate because of the voltage drop across the plate-load resistor changing as the plate current responds to the input signal. TUBE BIASING is the process of placing a dc voltage, usually negative, on the grid. Bias has several functions in circuit design. Biasing may be divided into two types: fixed and self . Tubes using fixed bias have a dc voltage applied to their control grids from an external source such as a battery. Self- 1-51 biasing voltages, on the other hand, are derived from current conducting through the tube. The most common types of self-biasing are cathode biasing and grid-leak biasing. The CLASS OF OPERATION OF AN AMPLIFIER is determined by the bias applied to a triode. An amplifier operating as class A conducts continually through the duration of the input cycle. Class AB operation occurs when the amplifier conducts for more than half but less than the entire duration of the input cycle. A class B amplifier conducts for only 50% of the input cycle. The class C amplifier conducts for less than half of the input cycle. TRANSIT TIME is the time required for electrons emitted by the cathode to reach the plate. Because transit time in a vacuum tube is considerably less than the speed of light, vacuum tube operation is affected at high frequencies. INTERELECTRODE CAPACITANCE is created by the naturally occurring capacitance between elements in a vacuum tube. One effect of interelectrode capacitance is to feed back a portion of the output 1-52 of a triode to the input. This effect is a prime-limiting factor in applying triodes. It is a major reason why triodes are seldom used — especially at the higher frequencies. MU AND TRANSCONDUCTANCE are measures of tube efficiency. Mu (p), or amplification factor, is a measure of the amount that plate voltage varies in relation to variation of the input voltage. Mathematically, mu (p) is expressed as AE P ae; TRANSCONDUCTANCE, on the other hand, is a measure of the amount of variation of plate current caused by a variation of the input signal. Mathematically, it is expressed as: TETRODES were developed to compensate for the effects of interelectrode capacitance. Placing a positively charged screen grid between the control grid and plate has the effect of adding a capacitor in series with the capacitance that exists between the control grid and plate. This reduces total capacitance below the value of either capacitor as shown by applying the formula: ClxC2 C1 + C2 1-53 + E bb + E bb TRIODE TETRODE SECONDARY EMISSION of electrons from the plate is caused by the acceleration of electrons by the screen grid. This causes the performance of a tetrode to be degraded. In addition to reduced amplitude, the output signals become noisy. PENTODES do not suffer from the effects of secondary emission. This is because a negatively charged suppression grid placed between the screen grid and plate forces any electrons emitted back to the plate. ANSWERS TO QUESTIONS Ql. THROUGH Q33. Al. By heating it. A2. Because the negatively charged electrons are attracted to the positively charged plate. A3. Filament and plate. A4. Negative. A5. Positive. A6. Pulsating dc. A7. Thoriated-tungsten and oxide-coated metals. A8. They reach operating temperatures quickly. A9. It serves as a mounting for the tube elements and as the terminal connection to the circuit. A10. The linear portion. All. Plate resistant R p . All. Peak Inverse Voltage (PIV). A13. The triode contains a third element called the control rid. A14. Because it is closer to the cathode. 1-54 A15. A plate load resistor R L A 16. To prevent them from drawing grid current. A17. The input signal A18. +275 volts. A19. a. 100 volts. b. 180° out of phase. A20. a. Cutoff. b. Saturation. A21. Cathode biasing. A22. Through the use of a bypass capacitor A23. rkg, the cathode to grid resistance. A24. Unequal charge and discharge paths of the coupling capacitor C c . A25. a. Class B. b. Class C c. Class A. A26. 42. A27. 340 volts. A28. The changes in plate current and grid voltage. A29. 240 volts. A30. The interelectrode capacitance (cpg) is divided between two series capacitances; thus, cpg greatly reduced. A3 1. Secondary emission, and noise. A32. Secondary emission. 1-55 A33. a. Plate, positive. b. Suppressor grid, negative. c. Cathode, can be negative, positive, or at dc ground potential, depending on biasing type. d. Control grid, negative. 1-56 CHAPTER 2 SPECIAL-PURPOSE TUBES LEARNING OBJECTIVES Upon completion of this chapter, you will be able to: 1 . Determine the number and type of individual tubes contained within the signal envelope of a multi-unit tube. 2. Explain the function and operating principle of the beam power tube and the pentode tube. 3. State the difference between the capabilities of conventional tubes and variable-mu tubes. 4. Describe the construction of uhf tubes, and explain the effects that ultra-high frequencies have on conventional-tube operation. 5. Explain the operation of gas-filled diodes, thyratrons, and cold-cathode tubes. 6. Explain the operating principles behind cathode-ray tubes, and the manner in which these tubes present visual display of electronic signals. INTRODUCTION TO SPECIAL-PURPOSE TUBES Because of their great versatility, the four basic tube types (diode, triode, tetrode, and pentode) covered in chapter 1 have been used in the majority of electronic circuits. However, these types of tubes do have limits, size, frequency, and power handling capabilities. Special-purpose tubes are designed to operate or perform functions beyond the capabilities of the basic tube types discussed in chapter 1. The special-purpose tubes covered in this chapter will include multi-unit, multi-electrode, beam power, power pentode, variable-mu, uhf, cold cathode, thyratrons, and cathode-ray tubes . MULTI-UNIT AND MULTI-ELECTRODE TUBES One of the probems associated with electron tubes is that they are bulky. The size of an electron tube circuit can be decreased by enclosing more than one tube within a single envelope, as mentioned in chapter 1. There is a large variety of tubes that can be combined into this grouping of "specialty tubes" called MULTI-UNIT tubes. Figure 2-1 illustrates the schematic symbols of a few of the possible combinations found in multi-unit tubes. 2-1 DUO- DIODE DUO-DIODE DUO- DIODE TWIN TRIODE TWIN PENTODE DIODE PENTODE TWIN TRIODE TWIN TRIOOE TWIN-INPUT TRIODE TRIODE TRIODE TWIN-DIODE PENTODE PENTODE TRIODE T W I N - DIOD E T W IN -D IOD E DIOD E T RIOD E TETRODE PENTODE PENTODE Figure 2-1. — Typical multi-unit tube symbols. An important point to remember when dealing with multi-unit tubes is that each unit is capable of operating as a separate tube. But, how it operates, either as a single tube or as a multi-unit tube, is determined by the external circuit wiring. When you analyze the schematic of a circuit, simply treat each portion of a multi-unit tube as a single tube, as shown in figure 2-2. 2-2 DUO-DIODE TETRODE DUO TRIODE PENTODE Figure 2-2. — Multi-unit tube Identification. Another type of special-purpose tube is the MULTI-ELECTRODE tube. In some applications, tubes require more than the three grids found in conventional tubes. In some cases, up to seven grids may be used. These types of tubes are called multi-electrode tubes and are normally classified according to the number of grids they contain. An example of this is illustrated in figure 2-3. Here, you see a tube with five grids; hence, its name is "pentagrid." The application of these tube types is beyond the scope of this module, but because multi-electrode tubes have been commonly used you should be aware of their existence. SUPPRESSOR GRID SIGNAL GRID CONTROL GRID PLATE SCREEN GRID CATHODE FILAMENT Figure 2-3. — Pentagrid multi-electrode tube. BEAM POWER AND POWER PENTODE TUBES The tube types you studied in the first chapter have one serious drawback; namely, they are not suitable as power amplifiers. Because of high-plate resistance and internal construction, tubes such as the triode, tetrode, and pentode are used only as voltage amplifiers. When power amplification is required (high-current requirements), special-purpose tubes called POWER PENTODES and BEAM POWER tubes are used. Figure 2-4 shows the arrangement of grids in a conventional pentode. The small circles depict cross sections of the grids. Notice that each grid is offset, or staggered, from the grid directly behind it. This arrangement of grids permits each grid to be exposed to the electron stream flowing from cathode to plate. 2-3 In this way, each grid will have maximum effect on the electron stream. There are two undesirable effects associated with the staggered grid arrangement that make it unsuitable for use in power amplifiers. CONTROL GRID SCREEN GRID CATHODE 1 SUPPRESSOR GRID ELECTRON PATHS Figure 2-4. — Electron flow in a conventional pentode. First, no direct path exists between the cathode and the plate. Electrons leaving the cathode must run an obstacle course around the grid wires to reach the plate. Some of these electrons are deflected by the grid and scattered and, thus, never reach the plate. Second, some electrons strike the grid wires and are removed from the electron stream as grid current. Because of these two undesirable effects, the amount of plate current that can flow through the tube is greatly reduced. Because of this loss of electrons from the stream, conventional tetrodes and pentodes are not suitable for power amplifiers. Therefore, a special class of tubes has been developed to overcome this problem — the BEAM POWER TUBES and POWER PENTODE TUBES. Figure 2-5 shows the cross section of the power pentode. Notice that there is no staggered grid arrangement. Instead, each grid wire is directly in line with the grid in front of and behind it. The screen and suppressor grids are shielded from the electron stream by the control grid. Because the screen grid is "shielded" by the control grid, it can draw little grid current from the electron stream. CONTROL GRID SCREEN GRID ELECTRON PATHS CATHODE PLATE SUPPRESSOR GRID Figure 2-5. — Electron flow in a power pentode. This arrangement of grids offers few obstacles to electron flow. Electrons will flow in "sheets" between the grid wires to the plate. The effect is to allow more of the electrons leaving the cathode to 2-4 reach the plate. Thus, the tube has the advantage of high power output and high efficiency. An added advantage to this type of grid arrangement is high-power sensitivity . This means that the tube can respond to much smaller input signals than the conventional electron tube. The reason for this is obvious; many more electrons reach the plate from the cathode. Therefore, large plate currents can be obtained from relatively weak input signals. Another type of power amplifier tube that is similar to the power pentode is the BEAM POWER TUBE. Beam power tubes have the same grid arrangement as the power pentodes. In addition, they use a set of beam-forming plates to force the electron stream into concentrated beams. Figure 2-6 depicts the internal construction of a beam-forming tube and its schematic representation. Notice that the beam- forming plates surround the grids and their supporting structures and are internally connected to the cathode. This internal connection ensures that the beam-forming plates are at the same negative potential as the cathode. Electrons that are emitted from the sides of the cathode are repelled from the grid supports and into the electron stream by the negative charge on the beam-forming plates. Electrons pass to the plate through the spaces between the beam-forming plates and, by doing so, are concentrated into beams. Because the beam-forming plates are at a negative potential, any electrons emitted by secondary emission are repelled back to the plate. The effect of the beam-forming plates is to increase the number of electrons in the electron stream by forcing stray electrons emitted from the sides of the cathode away from the grid supports and into the electron beam. Electrons that are deflected from the grid wires are also forced into the beam. This increases the total current flowing to the plate. For this reason, both beam-forming and power pentodes are suitable for use as power amplifiers. BEAM-FORMING SIDE VIEW ELECTRON STREAM CAT H COE Ft ATE SCREEN GRID GRID Ft ATE TOP VIEW BEAM- FORMING FtATES CONTROL GRID SCREEN GRID CATHODE r w T HEATER SCHEMATIC DIAGRAM Figure 2-6. — The beam-power tube. 2-5 VARIABLE-MU TUBES In most electron-tube circuits, the operating level of a tube is determined by the level of bias. When a negative-bias voltage is applied to the control grid of a tube, with no input signal, the conduction through the tube is reduced; thus the damage to the tube is minimized. There is one drawback to this. Because the control grid is already negatively charged by the bias voltage, the negative alternation of a large input signal will drive the tube into cutoff long before the positive alternation can drive the tube into saturation. Once the negative alternation reaches a certain level (determined by the bias voltage and tube characteristics), the tube simply cuts off. For this reason, conventional tubes, which you previously studied, are called SHARP-CUTOFF TUBES. Because of this sharp cutoff, the range of amplification of the conventional tube is limited by the bias voltage and tube characteristics. Once this range is exceeded, the output becomes distorted due to cutoff. In most applications, the sharp cutoff feature of conventional electron tubes causes no problems. However, in some applications electron tubes are required to amplify relatively large input signals without distortion. For this reason, the variable-mu tube was developed. VARIABLE-MU TUBES have the ability to reduce their mu, or (p), as the input signal gets larger. As the mu (p) decreases, the likelihood that the tube will be driven into cutoff decreases. (For an amplifier, this may appear to be self- defeating, but it isn't.) The idea is to amplify large input signals as much as possible without causing the tube to cutoff or create distortion. Because of their ability to avoid being driven into cutoff, variable-mu tubes are called REMOTE- CUTOFF TUBES. You should be aware, however, that a variable-mu tube can be driven into cutoff, but the amplitude of the input signal required to do so is considerably greater than in conventional sharp-cutoff tubes. The key to the ability of a variable-mu tube to decrease gain with an increase in the amplitude of the input lies in its grid construction. To understand how the unique grid construction of a variable-mu tube works, we will first examine the grid operation of a conventional tube during cutoff. Look at figure 2-7. Here, you see a diagram of a conventional sharp-cutoff triode with zero volts applied to the control grid. In view A, the majority of the electrostatic lines of force leave the positive plate (+) and travel unhindered between the evenly spaced grid wires to the negative cathode (-). Electrons emitted by the cathode travel along these lines from the cathode, through the grid spacings, to the plate. 2-6 GRID (OV ) CATHODE ELECTROSTATIC LINES OF FORCE +PLATE (A) (B) (Q Figure 2-7. — Cutoff in a conventional tube. In view B, a bias voltage of -6 volts is applied to the grid. As you can see, some of the electrostatic lines of force are attracted to the negatively charged grid wires while the rest pass through the grid spacings. Because there are fewer lines of force reaching the cathode, there are fewer paths for electrons to use to reach the plate. As a result, conduction through the tube is decreased. In view C, the negative potential of the grid has been raised to -20 volts, which drives the tube into cutoff. All of the electrostatic lines of force terminate at the negatively charged grid, instead of continuing on to the cathode. The electrons emitted by the cathode will not feel the electrostatic attractive force of the positively charged plate. Under these conditions, current cannot flow through the tube. Now look at figure 2-8. Here you see a diagram of a variable-mu, or remote-cutoff, tube. The only difference between the remote-cutoff tube depicted and the sharp-cutoff tube is in the grid wire spacing . In the conventional sharp-cutoff tube, the grid wires are evenly spaced, while in the remote-cutoff tube the grid wires in the middle of the grid are placed relatively far apart. This is shown in view A. 2-7 ELECTROSTATIC LIMES OF FORCE GRID -6V (C) GRID -20V Figure 2-8. — Grid operation in a remote-cutoff tube. In view B, the control grid is at zero potential (0 volts). Just as in the sharp-cutoff tube, electrons leave the cathode and travel along the lines of electrostatic attraction, through the spaces between the grid wires to the plate. In view C, a bias voltage of -6 volts is applied to the grid. Because of the close spacing of the grid wires at the ends of the grid, electrostatic lines of force at the ends are effectively terminated. The lines of force can only pass between the widely spaced grid wires closer to the center of the grid. In view D, the same negative potential -20 volts) is applied to the grid that caused the conventional sharp-cutoff tube discussed earlier to go into cutoff. This voltage is high enough to terminate most of the electrostatic lines of force on the grid wire. But, because of the wide spacing between the center grid wires, some electrostatic lines of force are still able to pass between the center grid wires and reach the cathode. Conduction will still occur in the tube, but at a reduced level. If the grid is driven even more negative, lines of force will be blocked from reaching the cathode, except at the very center of the grid. As you can see, the remote-cutoff tube, by its ability to reduce gain (conduction), handles large signals without going into cutoff. A variable-mu tube such as a 6SK7 with -3 volts applied to the grid will have a transconductance of about 2000 (p) mhos. If the grid is driven to -35 volts, the transconductance of the tube will decrease to 10 (p) mhos. This same increase in negative-grid voltage would have driven a conventional tube into cutoff long before the grid reached -35 volts. 2-8 Ql. What is the major dijference in grid construction between power pentodes and conventional pentodes ? Q2. Beam-forming tubes and power tubes are similar except that power pentodes lack what element? Q3. What effect does the shielding of the screen grid by the control grid have on plate current in beam-forming tetrodes? Q4. What effect does a large negative input signal applied to a variable-mu tube have on a. conduction through the control grid, and b. gain of the tube? Q5. Identify the type of electron tube(s) that would be most suitable for the following applications. a. Power amplifier b. Voltage amplifier with small signal inputs c. Low distortion amplifiers for use with large signal inputs SPECIAL UHF TUBES In the earlier discussion of conventional-electron tubes, you learned some of the limitations of tubes. One of these limitations was that the conventional tube was not able to operate (amplify) at extremely high frequencies such as those used in radar equipment. Even at frequencies lower than those used in radar equipment, problems occur. For example, at ultrahigh frequencies (300 MHz to 3000 MHz), transit time effects make the operation of a conventional-electron tube impossible. For this reason, the special ultrahigh frequency tubes were developed to operate within this frequency range. Before we discuss the way in which special uhf tubes counter the effects of transit time, you should understand the manner in which transit time affects conventional tubes. LIMITATION OF TRANSIT TIME We will explain the limitation of transit time by using figure 2-9. In view A, the positive-going alternation of a uhf ac signal is applied to the grid of a conventional-triode tube. The first positive-going alternation reduces the negative bias on the grid, and electrons start to move toward the grid. Since the input is an ultrahigh frequency signal, the majority of the electrons cannot pass the grid before the input signal progresses to the negative alternation. The electrons that have not yet passed the grid are either stopped or repelled back toward the cathode. This is shown in view B. Before these electrons can move very far, the second positive alteration reaches the grid, and causes even more electrons to move from the cathode (view C). At the same time, the electrons that were repelled from the grid toward the cathode by the first negative alternation feel the effect of the positive-going grid. These electrons reverse direction and again move toward the grid. Because these electrons had to first reverse direction, they are now moving slower than the electrons that are attracted from the cathode by the second positive alteration. The result is that the electrons from the cathode catch up to the slower moving electrons and the two groups combine (view C). This action is called BUNCHING. 2-9 Figure 2-9. — Effect of transit time at ultrahigh frequencies. In effect, the area between the grid and cathode becomes highly negatively charged, as shown in view D. This negative charge is surrounded by an electrostatic field. The electrostatic field cuts the grid and repels electrons that are present in the grid. As electrons are forced from the grid, the grid tries to go positive. Unfortunately, this tendency toward a positive charge attracts electrons from the mass or bunched charge. Thus, as an electron is forced from the grid; it is replaced by another from the massed charge. Electrons forced from the grid represent grid current (I g ), as shown in view E. The grid current flows from the grid through R g , to the cathode, from the cathode, to the massed charged, and back again to the grid, The movement of current in this manner is, in effect, a path for current flow from the cathode to the grid. Because current flows between the cathode and grid, the resistance (rgk) between these elements is lowered to the point of a short circuit . The grid, in effect, is short circuited to the cathode and ceases to function; and this, in turn, lowers tube efficiency dramatically. This is shown in view F of figure 2 - 9 . Transit time may be decreased by reducing the spacing between electrodes or by increasing the electrode voltages, which in turn increases electron velocity through the tube. The problem with the last solution is that the tube does not present an infinite resistance to current flow. If the operating voltage is raised to an operating potential that is too high, arcing ( arc over) occurs between the cathode and the plate and, most likely, will destroy the tube. For this reason, the effects of transit time are reduced in uhf tubes by placing the tube elements very close together. 2-10 UHF TUBE TYPES Uhf tubes have very small electrodes placed close together and often are manufactured without socket bases. By reducing all the physical dimensions of the tube by the same scale, the interelectrode- capacitance and transit time effects are reduced, without reducing the amplification capability of the tube. A disadvantage to this type of tube construction is that the power-handling capability of these tubes is also reduced due to the close placement of the tube elements. Uhf tubes are placed in three broad categories based on their shape and/or construction; ACORN, DOORKNOB, and PLANAR tubes. Acorn and Doorknob Tubes ACORN TUBES, as shown in figure 2-10, are available for use as diodes, triodes, or pentodes. Acorns are very small tubes that have closely spaced electrodes and no bases. The tubes are connected to their circuits by short wire pins that are sealed in the glass or ceramic envelope. Because of their small size, acorn tubes are usually used in low-power uhf circuits. HEATER CATHODE HEATER CONTROL GRID PLATE PLATE SCREEN GRI SUPPRESSOR GRID HEATER CA7HO DE HEATER Figure 2-10. — Acorn tubes. The DOORKNOB TUBE is an enlarged version of the acorn tube. Because of its larger physical size, it can be operated at higher power than the acorn tube. Planar Tubes PLANAR TUBES are so named because of their construction. The ordinary (conventional) tube you studied earlier uses concentric construction. This means that each element (cathode, grid, and plate) is cylindrical in shape. The grid is placed over the cathode, and the plate, which is the largest cylinder, is 2-11 placed over the grid. The result is a tube composed of concentric cylinders like the one shown in figure 2-11. Thus, the name concentric tubes. PLATE GRID CATHODE PICTORIAL DIAGRAM OF MECHANICAL STRUCTURE Figure 2-11. — Concentric construction of a conventional tube. At ultrahigh frequencies, the problems of producing small tube elements while reducing the spacing between elements become very difficult. Not only are the elements hard to keep parallel with each other during the manufacturing process, but they also have a tendency to warp and sag under normal operating conditions. Since these elements are already as close together as possible, any reduction in element spacing can cause arcing. Therefore, a new type of tube was developed to prevent arcing or element sagging in conventional tubes. This tube is known as the planar tube. Planar tubes are electron tubes in which the cathode, plate, and grids are mounted parallel to each other. Their physical construction greatly resembles a schematic diagram of a normal tube, as shown in figure 2-12. Figure 2-12. — Resemblance of a planar tube to a schematic diagram. 2-12 A typical planar tube is depicted in figure 2-13. Notice that the tube elements are mounted close to each other and are parallel to one another. The oxide coating of the cathode is applied to the top surface only. Therefore, the emitting surface of the cathode is parallel to the plate and the grid. GRID OX ID CATHODE GRID ENLARGEMENT OF CATHODE -GRID-PLATE AREA FILAMENT TUBE PIN GLASS WALLS PLATE CATHODE Figure 2-13. — Internal structure of a typical planar tube. The plate of the tube consists of a cylindrical stud. This stud-plate construction has two purposes. Its flat lower surface serves as a parallel plate, and its external upper end serves as the external-plate connection from the tube to the circuit. Because of its construction, the planar tube cannot use the ladder-type grid, with which you are familiar. Instead, the grid, formed into a circle, is composed of a wire mesh similar to that of a common screen door. The cathode structure is manufactured in two parts. Point A of figure 2-13 is the metallic shell of the tube and is used to couple (or connect) unwanted radio frequency signals from the cathode to ground. This connection is not, however, a direct coupling. The wafer at point C of figure 2-13 is composed of mica, which serves as a dielectric. The lower extension of the cathode serves as one plate of the capacitor, while the other plate is formed from the flattened upper portion of the cathode connector ring. The cathode has a direct connection to the tube pin through the connector labeled point B. You might think that this is a rather complicated method to connect the cathode to a circuit, but it serves a purpose. At high frequencies, the wiring of a circuit can pick up radio frequency signals and retransmit them. If the wiring involved happens to be the wiring used to supply dc voltages to the circuit, all the tubes in the circuit will receive the signal. The result will be massive distortion throughout the circuit. The problem can be eliminated by isolating the dc and radio frequency circuits from each other. In planar tubes, this is fairly simple. The point A ring is grounded. Any rf signals that the cathode may pick up through tube conduction are grounded or shorted to ground through the capacitive coupling with the point A shell. In other words, the point A shell (capacitive ground) serves the same function as the bypass 2-13 capacitor in a cathode-biased circuit. Because the capacitor will not pass dc, bias voltages can be applied to the cathode through the tube pins. Notice the external shape of the planar tube in figure 2-13. The tube is composed of five sections, or cylinders. As you go from the top to the bottom, each cylinder increases in diameter. Because of this piled cylinder construction, the tube resembles a lighthouse, and is therefore known as a LIGHTHOUSE TUBE. Another type of planar tube is shown in figure 2-14. This type of tube, because of its external appearance, is called an OILCAN TUBE. The major difference between it and the lighthouse tube is the addition of cooling fins to allow it to handle more power than the lighthouse tube. Because of their planar construction, both types of tubes are capable of handling large amounts of power at uhf frequencies. COOLING FINS COMMON ELECTRICALLY TO ANODE ANODE GRID HEATER CATHODE HEATER (INSIDE) Figure 2-14. — Oilcan planar tube. Q6. What effect does transit time have on a conventional triode operated at uhf frequencies? Q7. How do uhf tubes counter the effects of transit time? Q8. Why can acorn and doorknob tubes NOT handle large amounts of power? Q9. What type of uhf tube was developed to handle large amounts of power? GAS-FILLED TUBES You know that great effort is made to produce a perfect vacuum within electron tubes. But, even the best vacuum pumps and getters cannot remove all of the air molecules. However, the chances of an electron hitting a molecule in a near-vacuum are very slim because of the great distance between the molecules, compared to the size of the electron. An electron can pass between two molecules of air inside the tube as easily as a pea could pass through a circle with a diameter equal to that of the earth! In some tubes, the air is removed and replaced with an inert gas at a reduced pressure. The gases used include mercury vapor, neon, argon, and nitrogen. Gas-filled tubes, as they are called, have certain 2-14 electrical characteristics that are advantageous in some circuits. They are capable of carrying much more current than high-vacuum tubes, and they tend to maintain a constant IR drop across their terminals within a limited range of currents. The principle of operation of the gas-filled tube involves the process called ionization . ELECTRICAL CONDUCTION IN GAS DIODES An operating gas-filled tube has molecules, ions, and free electrons present within the envelope. In a gas-filled diode, the electron stream from the hot cathode encounters gas molecules on its way to the plate. When an electron collides with a gas molecule, the energy transmitted by the collision may cause the molecule to release an electron. This second electron then may join the original stream of electrons and is capable of freeing other electrons. This process, which is cumulative, is a form of ionization. The free electrons, greatly increased in quantity by ionization, continue to the plate of the diode. The molecule which has lost an electron is called an ion and bears a positive charge. The positive ions drift toward the negative cathode and during their journey attract additional electrons from the cathode. The velocity of the electrons traveling toward the plate varies directly with the plate voltage. If the plate voltage is very low, the gas-filled diode acts almost like an ordinary diode except that the electron stream is slowed to a certain extent by the gas molecules. These slower-moving electrons do not have enough energy to cause ionization when they hit the gas atoms. After the plate voltage is raised to the proper level of conduction, the electrons have enough energy to cause ionization when they hit the gas molecules. The plate potential at which ionization occurs is known as the IONIZATION POINT, or FIRING POTENTIAL, of a gas tube. If the plate voltage is reduced after ionization, it can be allowed to go several volts below the firing potential before ionization (and hence, high-plate current) win cease. The value of the plate voltage (E p ) at which ionization stops is called the DEIONIZATION POTENTIAL, or EXTINCTION POTENTIAL. The firing point is always at a higher plate potential than the deionization point. GAS TRIODE The point at which the gas ionizes can be controlled more accurately by inserting a grid into the gas diode. A negative voltage on the grid can prevent electrons from going to the plate, even when the plate voltage is above the normal firing point. If the negative-grid voltage is reduced to a point where a few electrons are allowed through the grid, ionization takes place. The grid immediately loses control, because the positive ions gather about the grid wires and neutralize the grid’s negative charge. The gas triode then acts as a diode. If the grid is made much more negative in an effort to control the plate current, the only effect is that more ions collect about the grid wires — tube continues to conduct as a diode. Only by removing the plate potential or reducing it to the point where the electrons do not have enough energy to produce ionization will tube conduction and the production of positive ions stop. Only after the production of positive ions is stopped will the grid be able to regain control. Such gas-filled triodes are known as THYRATRONS. Thyratrons are used in circuits where current flow in the thyratrons output circuit is possible only when a certain amount of voltage is present on the thyratrons grid. The flow of plate current persists even after the initiating grid voltage is no longer present at the grid, and it can be stopped only by removing or lowering the plate potential. The symbols for the gas-filled diode, the voltage regulator, and the thyratron are the same as those for high-vacuum tubes except that a dot is placed within the envelope circle to signify the presence of gas. Some examples of gas-filled tube schematic symbols are shown in figure 2-15. 2-15 GAS DIODE THYRATRON V-R TUBE NEON-GLOW LAMP Figure 2-15. — Schematic diagram of gas-filled tubes. Before leaving this section, you should be aware of one precaution associated with mercury-vapor tubes. The mercury vapor is not placed in the tube as a vapor; instead a small amount of liquid mercury is placed in the tube before it is sealed. When the liquid mercury comes in contact with the hot filament, the mercury vaporizes. To ensure that the mercury has vaporized sufficiently, the filament voltage must be applied to mercury-vapor tubes for at least 30 seconds before the plate voltage is applied. If vaporization is incomplete, only partial ionization is possible. Under these conditions, the application of plate voltage results in a relatively high voltage drop across the tube (remember E = I x R), and the positive ions present are accelerated to a high velocity in the direction of the cathode. As the ions strike the cathode, they tear away particles of the emitting surface, usually causing permanent damage to the cathode and the tube. When the mercury is completely vaporized, the action of the gas is such that the voltage drop across the tube can never rise above the ionization potential (about 15 volts). At this low potential, positive-ion bombardment of the cathode does not result in damage to the emitting surface. Generally, when gas-filled tubes are in the state of ionization, they are illuminated internally by a soft, blue glow. This glow is brightest in the space between the electrodes and of lesser intensity throughout the remainder of the tube envelope. This glow is normal and must not be confused with the glow present in high-vacuum tubes when gases are present. A high-vacuum tube with a bluish glow is gassy and should be replaced. The ionization of these gases will distort the output of the tube and may cause the tube to operate with much higher plate current than it can carry safely. COLD-CATHODE TUBES The cold-cathode, gas-filled tube differs from the other types of gas-filled tubes in that it lacks filaments. Thus, its name "COLD-CATHODE TUBE." In the tubes covered in this text thus far, thermionic emission was used to send electrons from the cathode to the plate. This conduction of electrons can be caused in another manner. If the potential between the plate and the cathode is raised to the point where tube resistance is overcome, current will flow from the cathode whether it is heated or 2-16 not. In most applications in electronics, this method is not used because it is not as efficient as thermionic emission. There are two applications where cold-cathode emission is used. The first application you are already familiar with, although you may not be aware of it. Every time you look at a neon sign you are watching a cold-cathode tube in operation. Thus, the first application of cold-cathode tubes is for visual display. You are also familiar with the reason for this visual display. In the NEETS module on matter and energy, we explained that when energy is fed into an atom (neon in this case), electrons are moved, or promoted, to higher orbits. When they fall back, they release the energy that originally lifted them to their higher orbits. The energy is in the form of light. Cold-cathode tubes are also used as VOLTAGE REGULATORS. Because voltage regulators will be dealt with extensively in the next chapter, we will not cover their operation now. At this point, you only need to understand that a cold-cathode tube has the ability to maintain a constant voltage drop across the tube despite changes of current flow through the tube. The tube does this by changing resistance as current flow varies. Examine figure 2-16. Here you see a cold-cathode tube connected to a variable voltage source. The variable resistor rkp does not exist as a physical component, but is used to represent the resistance between the cathode and the plate. Most cold-cathode tubes have a firing point (ionizing voltage) at about 115 volts. Thus, the tube in view A of the figure is below the firing point. Because the tube lacks thermionic emission capabilities, no current will flow and the tube will have a resistance (rkp) near infinity. The potential difference between the plate and ground under these conditions will be equal to the source (E bb ) voltage, as shown on the voltmeter. E bb Ebb E hh (A)